harey
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Posts posted by harey
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What is the probability that George's pile is the (n-minus) mirror of Lennies?
They can follow other than mirror paths to meet at the same point.
If they meet, they meet at the diagonal. The probability (for each one) to get to a particular point on the diagonal is:
Pascal's triangle/(2 power n).
I hope someone finds a formula for the product.
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Well, Freddie overlooked that the grass continues to grow. Whether it is an assumption?
I rather fear that we have to assume that the same amount of grass grows every day, regardless of the stock. Maybe a farmer could confirm.
a - stock of grass
b - day's growth
c - quantity eaten by a cow a day
1) a+3*b=6*3*c
2) a+7*b=3*7*c
1)-2) 4b=3c
So one cow needs 3/4 of a day to eat one day's increase, leaving 1/4 of a day to eat the stock. If I did not miscalculate, 63/4 days. -
Based on a similar problem, the prisoners form a line with following rules:
a1) if there are less than 2 colours, take any place;
a2) otherwise take place between.
This way, prisoners are sorted R.....RRRrbBBB...B (or B...BBBbrRRR....R).
b1) 98 prisoners go for sure
b2) the remaining 2 prisoners guess at random.
This strategy can be refined so that everybody knows his colour.
As the PO cannot do anything to foil it, there will be two Best Answers.
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If I posted this problem, I would ask to clarify:
1) why the lines H and I cannot be parallel;
2) crossing trajectories do not necessarily imply that the ships collide.
BTW, the sea should be endless (so that H does not reach her destination before colliding).
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Let A = (volume of consumed fuel) / (distance traveled consuming the fuel)
Then A is the area, perpendicular to the direction of travel, that sweeps out a volume equal to the consumed fuel as the vehicle moves forward.
A gets bigger when you accelerate, smaller when you coast.
In the U.S. scenario, if you poured fuel into a tank with cross section A, the fuel would rise to a height in that tank equal to the distance the vehicle would travel in consuming that fuel..
You got the first part to 97% - I wanted to hear "section of a pipeline along the trajectory". The tank of the U.S. scenario corresponds quite well to the pipeline, just the section of a tank is not measured in 1/m2, so the second part of the problem is still open.
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Place four unit squares into the corners of the resulting square and the 5th one into the middle after a 45 degree rotation.
The diagonal of the new square:
d=sqrt(2)+1+sqrt(2)
giving the surface 4.5+2*sqrt(2) (about 7.33). -
I agree. (I just wanted to be VERY clear.)
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"Rectangular Parallelepiped"s are usually not used to transport fuel.
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Though correct, a little wordy. Can you imagine a physical object fitting this definition?
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In Europe, we measure the fuel consumption in litres per 100 km. It is quite convenient because I can easily figure out what a litre is (a little bit less than one and half standard wine bottle) and it is not hard to figure out a distance of 100 km. However, any teacher of physics would point out that volume should be measured in [m3] and distance in [m]. After simplification, I get that fuel consumption should be measured in [m2]. What does it represent?
In the U.S., the consumption is measured in miles/gallon. Quite convenient, too, just that in the MKSA system, I get [1/m2]. How do you represent that?
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Away with equations!
Is there a solution w/o equations? I mean more simple?
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If the boy runs toward the train, the train makes a certain distance.
If the boy runs away from the the train, the train makes the same distance plus the bridge.
In the second case, the boy ran 1/7th of the bridge more, the train the whole bridge more. So the train is seven times faster than the boy. -
Still unsolved... I tried to omit chunks that are contained in other chunks (i.e. TGTGA is there twice and is contained in TGTGACA). I hoped that with the reminder I would be able to build longer chunks. Still too many combinations.
How is it done in praxis?
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Borrow money:
ASSETS:
Cash: 100$
Total: 100$
LIABILITIES:
Father: 50$
Mother: 50$
Total: 100$
Buy the phone:
ASSETS:
Cash: 3$
Phone: 97$
Total: 100$
LIABILITIES:
Father: 50$
Mother: 50$
Total: 100$
Return 1$
ASSETS:
Cash: 1$
Phone: 97$
Total: 98$
LIABILITIES:
Father: 49$
Mother: 49$
Total: 98$
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one of them can offer a low amount of money (so that it does not matter who starts). In turn, each one can raise or pass. After two subsequent passes, the last one who raised decides where to go, pays the bill and divides the reminder between the other two.
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2*n. As we are conditioned to cut a pizza through the centre, each cut will double the number of pieces. As the cuts are random, the pieces will not be of same size.
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I know a better variant: 6 butts, you need 3 butts to make a cigarette.
Grazing cows
in New Logic/Math Puzzles
Posted
The first part did not require much calculation
. As usually, I made an arithmetic error. I tried with b=60, c=80 - plasmid is correct.