DeGe
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Posts posted by DeGe
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S 34- 1
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Ask the server for time. Let us say you sent the request at time T; this request reaches the server at time T+t1. The server sends the time T+t1.
So, you get the time T+t1, but the actual time now is T+t1+t2 when you get the time.Program such that you send another request at the very instant you get the first response from the server.
So, at time T+t1+t2, you send the second request, and the time you receive from the server is T+2t1+t2 while the actual time is T+2t1+2t2 when you get this time.
Calculate the difference between the two times recieved. You now know how much is t1+t2.Now, ask the server to send to send you the time (Tn) exactly n seconds later; for example you ask the server what time will it be after 30 seconds.
As before, you will get the time Tn+t1, when the actual time is Tn+t1+t2.
Subtract t1+t2 from the time Tn+t1 received from the server and set your computer clock to Tn after n seconds.
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i see the error. Dont have time now but will correct it later
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The problem statement says
- "His truck can only hold 1000 apples."
the update says that the store is 1000 miles away
If the driver starts with a full load [1000 apples] and drives 1000 miles, he will have 0 apples left upon arrival.
Thus, unless he can ferry apples to some point(s) in between and then move these forward, there is no way to every deliver even 1 apple.
If we assume that there is a point halfway [500 miles] then he could do the following:
- leave the warehouse with 1000 apples
- drive 500 miles [now has 500 apples]
- leave the apples at the halfway point [now has 500 apples]
- drive back to the ware house
- leave the warehouse with 1000 apples
- drive 500 miles [now has 500 apples]
- Picks up 500 the apples at the halfway point [now has 1000 apples in the truck and 0 apples at the halfway point]]
- Drives the remaining 500 miles to the store and delivers 500 apples
Thus for 2 trips[500 and 1000 miles one way (3000 miles total round trip)] 500 apples can be delivered
to deliver 3000 apples would require:
- an interim storage area at 500 miles
- 6 "short" round trips between the warehouse and the interim storage area [1000 miles R/T each]
- 6 "long" round trips from the warehouse [stopping at the interim storage area to reload] to the store [2000 miles R/T each]
Notes:
- you can break this up many ways
- it is not clear what the optimal interim storage area distance [from the ware house] is [and if more than 1 helps]
Yes, but for returning also he would need to eat apples
So, if he goes 500KM, he would eat 500 while going and 500 while coming back.
533
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Each digit repeats itself in each position as follows:
in ones position 1000 times
in tens position 100 times
in hundreds position 10 times
in 1000 position 1 times
and 1 appears once in 10 000
Now, 0 + 1 + 2 +3 .... + 9 = 45
So, sum of digits is 45*1000 + 45*100 + 45*10 + 45*1 + 1 = 45*1111 + 1 = 49996
True or False Quizes
in New Logic/Math Puzzles
Posted
From what I remember while solving it, there were no unresolved elements and each piece fitted in one place only (I have now deleted the file that I used to work this out).
The interchangeability between Mike/North and Paul/Fisher is also resolved. I don't remember how exactly I resolved it but it had something to do with there being only 3 girls names... Grace, Karen, and Dot. In case of interchanging Paul/Fisher and Mike/North, some other condition was being violated.