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petar

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  1. Actually I think 99 - 0 - 1 would be the solition
  2. I think the solution is: only 3 pirates left, the elder one will get 0 laptops, because his priority is not to die over having Laptop, then he propose all the 100 laptops to the second pirate and 0 to the third, that way he gets the most votes and doesn't die. This could not apply for 4 or more because they would have to split the laptops and if they split them then they would prefer to kill the first pirate. What do you Think?
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