jmaurier

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About jmaurier

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  1. minimum 3 max 6 (If you are splitting into 3 piles each time). incase you don't know: "!=" means "not equal" BEST CASE = 3 tries 1)if A=B then the coin is in C. Split C into three piles (again A,B,C) 2)if A=B then the coin is in C again. Split C into the three last coins. 3)if A=B then C is the coin. WORST CASE = 6 tries 1)A!=B (piles of 9) 2)Now test A and C if A=C then split B into ABC if A!=C then split A into ABC 3)A!=B (piles of 3) 4)Now test A and C if A=C then split B into ABC if A!=C then split A into ABC 5)A!=B (last 3 coins) 6)Now test A and C if A=C then B is the coin if A!=C then A is the coin