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Rob_Gandy

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Posts posted by Rob_Gandy


  1. granted, as a result you often find yourself speaking other languages involuntarily to people.

    i wish for virtue.

    Your wish is my command. After a number of minutes with no changes you question where your virtue is. With a smile I say, "I guess you will have to wait and see..."


  2. Okay, but it's twenty times as expensive.

    Hmm...what's an interesting wish...

    ...okay, I wish there was a threshold IQ for people to vote for president of the US, congress, governors etc.

    Your wish is my command. The threshold is....how about 60. Your IQ has to be lower than that to vote. Plus it is illegal to require someone to take a test to be able to vote so enjoy prison.

    • Upvote 1

  3. If a mod is reading this, it should probably be moved to the Games section.

    Granted, but it turns out that the universe is completely deterministic and nothing is decided by luck.

    I wish for all the dirty dishes piling up in my sink to be cleaned, undamaged, not poisoned, not on fire or at any reasonable risk of combustion, and sitting in their proper places in my cabinets. ("Sitting" implies that they are at rest and not traveling at near-light speed about to bore a hole through the walls.)

    Your wish is my command. The dishes begin to wash themselves in the sink and put themselves away....but they forget to turn the sink off. Your apartment/house is now flooded ruining everything and your water bill is astronomical.


  4. OK, but you can only maintain that form when you have perfect focus (aka you can't walk or talk or move)

    Otherwise you will be a formless ooze.

    I wish to know the winning numbers for the next 20 lotteries.

    Your wish is my command. They are 43 3 23 5 32 12 56 8 32 12 12 34 54 7 6 32.......etc. in no particular order.


  5. put all the non-sin(x) terms on other side of equation to get

    sin(x)*(x^6-14x^5+69x^4-126x^3-22x^2+308x-240) = (x^6-14x^5+69x^4-126x^3-22x^2+308x-240)

    Let y = (x^6-14x^5+69x^4-126x^3-22x^2+308x-240)

    sin(x)*y = y

    If y != 0, then we have sin(x) = 1, which is true for x = pi/2 + 2*pi*k for any integer k.

    if y == 0, then we need to find the roots of the polynomial

    y = (x^6-14x^5+69x^4-126x^3-22x^2+308x-240)

    Looking at the prime decomposition of 240,

    we get 240 = 2^4*3*5

    This makes it seem likely that (x-5), (x-3), and (x-2) are factors.

    Polynomial long division to get

    y/((x-5)*(x-3)*(x-2)) = x^3-4x^2-2x+8

    Prime decomp of 8 is 2^3,

    (x-2) doesn't work, try (x-4) [which agrees with hint]:

    success:

    y/((x-5)*(x-4)*(x-3)*(x-2)) = x^2-2

    x^2-2 = 0 if x = plus/minus sqrt 2

    Therefore......

    roots are:

    2,3,4,5, +sqrt(2), -sqrt(2), [pi/2 + 2*pi*k for any integer k]

    I started by writing it as (sin(x)-1)(polynomial)=0. The rest is basically the same.


  6. As far as the video goes, I think the problem comes with working with only the extremes. Absolutely nothing happens or the worst thing imaginable happens. We take no action or we take extreme action. So the analysis of the situation, the possible outcomes and the number of possible actions are limited.


  7. :)

    Correct-a-mundo.

    Point at a card, and ask if some other card is an Ace.

    Say you are pointing at A, and you ask about B (C is the remaining card).

    If A = Ace and B = Ace, then he will say Yes ---> Choose B

    If A = Ace and B = Jack, then he will say No ---> Choose C

    If A = Jack and B = Ace, then he will say ? ---> Doesn't matter which of B or C you choose, you will get an Ace since A is the Jack, so can still follow same rule above.

    Here is Hint Puzzle 2:

    Suppose that somehow, you have learned that you are speaking not to Random but to True or False -- you don't know which -- and that whichever god you're talking to has condescended to answer you in English. For some reason, you need to know whether Dushanbe is in Kirghizia or not. What one yes-no question can you ask the god from the answer to which you can determine whether or not Dushanbe is in Kirghizia?

    It would be the standard, "If is asked you yesterday how would you respond?"


  8. I'd say 'Can you find all the roots?,' but I know this will get solved. ^_^

    This problem was posted a few years ago in the math department of the college I attended. I got a math club t-shirt and a certificate for getting the correct answer.

    Find all the roots of the following equation without the use of technology.:

    x6sin(x)+240-14x5sin(x)-308x+69x4sin(x)+22x2-126x3sin(x)+126x3-22x2sin(x)-69x4+308xsin(x)+14x5-240sin(x)-x6=0

    There are four consecutive integer roots.


  9. There are 3 smaller, easier puzzles that may serve as hints to building up the answer to this one.

    I will post the first one below. Those with pride, feel free to not look.

    Noting their locations, I place two aces and a jack face down on a table, in a row; you do not see which card is placed where. Your problem is to point to one of the three cards and then ask me a single yes-no question, from the answer to which you can, with certainty, identify one of the three cards as an ace. If you have pointed to one of the aces, I will answer your question truthfully. However, if you have pointed to the jack, I will answer your question yes or no, completely at random.

    I would ask, "Is the card to the right/left an ace?" If yes pick that one if no pick the other one. Still trying to apply that to the OP though.


  10. Assuming if you ask a god a question they can't answer, they'll say nothing or something completely different that means, like, 'error'...

    Ask two of them "If I ask you next 'Is the sky blue', will you answer da or ja?"

    If one can't answer, he is the random answerer, otherwise both will answer which ever is yes and the third is the random.

    Third question, ask one that answered yes to the first question, "Is the sky blue?" to discern if liar or truth teller.

    Will they try to be tricky and answer the question as "If I ask you a question will you answer with either da or ja?" True would say yes, False no and Random either. So assuming you can pose a question the Random can't answer, I would change the first question to "If I ask you next 'Is the sky blue', how will you respond?"

    Now, I'm assuming that no matter what question you pose they will all be able to answer, so I'm still stumped for now.


  11. A. Is your answer to this question a lie? OR B. Is your answer to this question the truth? Anyone you ask A will answer No and anyone you ask B will answer Yes. This will let you know which word is yes and which is no.

    I think this is where I would start. Still working on Q#2 and 3.


  12. Figuring the 5878* and 12547* was fairly easy. I did trial and error to get the last two *.

    . . . . . . . . . . . . 5 8 7 8 1

    . . . . . . .--------------------

    1 2 5 4 7 3 / 7 3 7 5 4 2 8 4 1 3

    . . . . . . . 6 2 7 3 6 5

    . . . . . . . -------------

    . . . . . . . 1 1 0 1 7 7 8

    . . . . . . . 1 0 0 3 7 8 4

    . . . . . . . -------------

    . . . . . . . . . 9 7 9 9 4 4

    . . . . . . . . . 8 7 8 3 1 1

    . . . . . . . . . -------------

    . . . . . . . . . 1 0 1 6 3 3 1

    . . . . . . . . . 1 0 0 3 7 8 4

    . . . . . . . . . ---------------

    . . . . . . . . . . . 1 2 5 4 7 3

    . . . . . . . . . . . 1 2 5 4 7 3

    How......? I had no clue where to even start on this one. What was your process for finding the numbers?

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