OMGTHATSIT

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About OMGTHATSIT

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  1. OMGTHATSIT added an answer to a question Help! A remainder is chasing me   

    if you check out each number out each number's posiblities and put it into a formula, you will obtain:

    for the number 2: (x is any natural number, and it's diferent for every equation)

    1+ 2x

    Number 3

    29+30x

    Number 4

    19+ 20x

    Number 5

    9+ 10x

    Number 6

    29 + 30x

    Number 7

    69 + 70x

    Number 8

    39 + 40x

    Number 9

    89+90x

    Number 10

    9 + 10X

    So we need a number that is equivalent to all those equations. we have:

    1+2X

    29+30X

    19+20X

    9+10X

    69+70X

    39+40x

    89+90X

    So, we go and analyse the equations who give bigger products for the smallest number of X. those are: 89+90x and 69 + 70x. Replacing one of the x for another letter (y) we get:

    89+90y = 69 + 70x <=> 20 = 70x - 90y

    With that, we can now replace the "x" and the "y". for that formula to work, after some calculations, I notice that the x must go for 8 + 9z and the y must go 6+7z

    So, starting for the 1st, if z = 0, x=8 and y=6. we replace them in the equation

    89 + 90 x 6 = 629.

    However, this number doesnt exist on the equation 39+40x, so its invalid.

    You keep going,

    z=1; x= 17 and y = 13, the final =1259, also doesnt exist on the equation 39+40x, so its invalid.

    z=2, the final is 1889, also invalid.

    Then, finally, z=43 y = 6+(7x3) =27........ 89 + 90x27 = 2519; which is valid for all the equations.
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