andaryfaysal
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The first can only guess it right if the two othes have the same color so:
P_1 = P(ww.bb.bb)+P(bb.ww.ww) = (3/14)^2 * 2 = 9/98 = 9.2%
similarily:
P_2 = P(bb.ww.bb) + P(ww.bb.ww) = P_1 = 9.2%
the third has the following extra advantage:
P_3 = P(bb.bb.ww) + P(ww.ww.bb) + P(bb.ww.bw) + P(ww.bb.bw) = P_1 * 2 = 18.4%
the forth turn (first chair)
P_4 = P(bw.ww.bw) + P(bw.bb.bw) = (3/14) * 2 = 42.9 %
the fifth turn (second chair) or more
P(>5) = 1 - (P_1 + P_2 + P_3 + P_4) = 20.3%
which is lower than the previous seat. therefore, I would choose the first seat since the student on the forth turn has the highest probability.
Please let me know if I missed something.
Which Chair you will choose ?
in New Logic/Math Puzzles
Posted
"interesting". This means the puzzle is so good that it got each one of us to think differently. Thank you for the brain teaser, ujjagrawal.
Although after going through the posts, I am now convinced that bonanova has nailed the answer.