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andaryfaysal

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Posts posted by andaryfaysal

  1. The first can only guess it right if the two othes have the same color so:

    P_1 = P(ww.bb.bb)+P(bb.ww.ww) = (3/14)^2 * 2 = 9/98 = 9.2%

    similarily:

    P_2 = P(bb.ww.bb) + P(ww.bb.ww) = P_1 = 9.2%

    the third has the following extra advantage:

    P_3 = P(bb.bb.ww) + P(ww.ww.bb) + P(bb.ww.bw) + P(ww.bb.bw) = P_1 * 2 = 18.4%

    the forth turn (first chair)

    P_4 = P(bw.ww.bw) + P(bw.bb.bw) = (3/14) * 2 = 42.9 %

    the fifth turn (second chair) or more

    P(>5) = 1 - (P_1 + P_2 + P_3 + P_4) = 20.3%

    which is lower than the previous seat. therefore, I would choose the first seat since the student on the forth turn has the highest probability.

    Please let me know if I missed something.

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