dark_magician_92
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Posts posted by dark_magician_92
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was the answer i posted, wrong? Age - 135, number-17640
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i am getting the same answer but diff. Probabilities. Fermat-30%, Galois - 27.2%, Hilbert - 42.8%.
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if by being 1.5 times gigger, you mean 1.5 times populated, then zog has 75, zod has 250, zop has 175, zob has 150 and zoz has 100 zoxians
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the diffr b/w 1st and tnd no. Is 28203 which has 4 factors 3,7,17,79. Now 28203 must be a factor of the no. Which when acts as divisor, leads to same remainder. only 79, out of the 4 factors divides the diff of 3rd and 2nd no, so answerr should be 79
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2.01 approx.
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8:25 am
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max-3 and min-1
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oh, i am sorry, just realised i had a calculation mistake earlier - none of 1st type, 400 of 2nd, 150 of 3rd and 400 of 4th type.
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400 of 1st type, 150 of 2nd and 400 of 4th type
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don't know how to solve 3 variable inequalities but
from carpentary eqn we can deduce that the 1st'eqn can be reduced to 8d+6t+c<=32. So By making few cases, one can find that max revenue is when d=1,t=1,c=9. But don't know hw to do w/o making cases
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is this right?
25 tons of alloy1, 50 tons of alloy2 and 25 tons of alloy 3. No need of alloy 4. We will get profit of 1000$
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8/107 using bayes theorem
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3 liters
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5 are known to me, and 5 to my wife? I found out that the sum of ppl known to a person amd his spouse is =10, and since all except me know diff no. Of ppl,then 5+5 case has to be avoided. So it should be for me n spouse
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oh yeah i forgot expected value can be a fractions. Your eatimation is right, i rounded it off without thinking.
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since there are g.father and g.mother involved, we have 3 generations at least. The mother in law and father in law helps in idenrifying that they have a son who is married to a woman. the two fathers would be the g.father and his son, similar logic for 2 moms. Now there are 3 grandchildren and the 4th child is the son of the g.father and g.mother. There are 2 sisters and 1bro, so the 3 children can be 1 boy, 2 girls and all rest conditions are satisfied by the grp of these 7 ppl
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no. Of trailing zeroes should be equal to 12
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any explanation please
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with this above hint/spoiler
the answer is 231, phillip has it
Probability of a rope cut exactly in half, in a single slice
in New Logic/Math Puzzles
Posted
i agree to the anza and kop. Tha answer can't be 1/3 because the concept is that if you divide the case in 3 possibilities and all cases have equal possibilities, only then one of the case has the prob = r/y. Hence in this case prob. Of cutting in middle is not as same as cutting less than or more than half, so 1/3 doesnt work.