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Posts posted by wolfgang

  1. 17 hours ago, wolfgang said:

    As the numbers are from 1 to 6  that means it may have a relation to dice ( by using two dice):

    11 means A

    12 means B

    21 means C

    something like that...



    e.g.( As the numbers are from 1 to 6  ) can be written like this: 1126621531323323123152261152311452242363622464

  2. The Big Bang theory is the prevailing cosmological model for the universe from the erliest known periods through its subsequent large-scale evolution.The model accounts for the fact that the universe expanded from a very high density and high temperature state Some estimates place this moment at approximately 13.8 billion years ago, which is thus considered the (age of the universe) After the initial expansion, the universe cooled sufficiently to allow the formation of subatomic particles, and later simple atoms. Giant clouds of these primordial elements later coalesced through gravity to form stars and galaxies.

    My question was so: what if  the whole universe was inside a colsed room? and the galaxies were just like  dust particles hanging there , if these paricles are subjected to a continuous  diverging gravity  ,so they will expand.

    That means , that there was NO  start point and NO Big bang theory !

    What do you think?


    New anti-Big bang Theory.png

  3. We should devide the 12 coins into three groups, 5,5,and 2

    1- for the first  five, we weigh 2 against 2, leaving one  coin aside.

       a- if they are blanced,we put them  aside.

       b.- if they are´nt  balanced.

            we should weigh the heavier two with any other two coins :- now... if they balanced so the counterfeit coin is one of the  two light coins,which will be easy to be find with the               third weigh.....and if they are heavier,then we should weigh them one against one,,,and they heavier is the counterfeit coin.

    2- for the 2nd five .we will do the same 2 against 2,leaving one coin aside:-

        a- if  they are balanced,  so one of the two coins left aside is the counterfeit coin, which will be easy to find with the 3rd weigh.

        b- if they are not balanced....see above.

  4. On 25.3.2016 at 2:13 AM, Mr.Dog said:

    Alright, think i got it after fiddling with the unique number values for the letters.

      Hide contents

    Sol. abedcg = 5

    ( a=6 , b = -2 , c = 3 , d = -8 , e = 2, f = -1 , g = 4),


    1. fedcg=abcdef            2. (fg)(bc)= (3)+(1)=4       3. (ab)cdef=0 ---> (g)cdef=0 ----> (gf)cde=0---> 3cde=0          



    4. Trial and error with abged = 2 , abgcd = 3 and 3cde = 0, easier when you know that g=ab. 

    abcdef = 0
    bc = 1
    abged = 2
    abgcd = 3
    fgbc = 4
    abedcg = 5
    afedcg = 6
    abc = 7


    Amasing!!! you did find all the sequences from 0 to 7 ...but  5 is wrong..

  5. with 5

    1st. 5
    2nd 1
    1st 5, 2 ( 5+2=7...he needs 8)
    2nd 1,8 to prevent the 1st player to use it...( 1+8=9... the 2nd player needs 6 )
    1st 5,2,6 to block the 15 for the 2nd...( 5+2+6=13... he needs 2)
    2nd 1,8,2 blocking the 15 for the 1st.
    1st 5,2,6,4 and wins because(5+6+4= 15)
    The same will be true for all other numbers choosed by the 2nd. player and the 1st. player will win
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