fabpig
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Posts posted by fabpig
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And can I wear my lipstick? Put lipstick on a pig etc etc
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whoops, Forgotten all about this. Wish I had the story-telling ability of the other contributers, but
THTIWFSTLR
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DOWN
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Packers ++
Giants -
Eagles -
Atlanta Falcons - 21
Carolina Panthers - 20
Dallas Cowboys - 18
New Orleans Saints - 16
Seattle Seahawks - 16
Washington Redskins - 15
Detroit Lions - 15
St. Louis Rams - 15
San Francisco 49ers - 15
Chicago Bears - 15
Arizona Cardinals - 14
Green Bay Packers - 14
New York Giants - 14
Philadelphia Eagles - 10
Minnesota Vikings - 5
Knocked Out
16. Tampa Bay Buccaneers
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SAPPED
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so what were the other 485? If you're claiming that they're boys, then that makes 485*2 boys = 970 + (244 out of your 515 families) which leaves 786 children of whom 271 are girls.and the other 515 are ???.
Or are you taking it that the girl you've been introduced to is the eldest child?
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OK here we go
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(9 letters)
Edit...oh, yeah. Nice scoring ,Thal.
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Apart from 1 thing...........If one of the 2 children is a boy, the chance of the other being a girl is 2/3
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HAPPEN
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_ _ _ _ A _ _ HUBCAPS - 1 REPLATE - 1 REPLIED - 0 REPLETE - 0 BOBCATS - 1 HUNDRED - 0 SARONGS - 0
Thalia +5
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Ummm... I didn't read this entire thread (waste of time), but the issue here is simply a combination/permutation issue.
Since it doesn't matter whether the child stated as the girl is the first born or second born, there isn't as many scenarios as the "answer" claims.
A child is a girl
Possibilities:
Girl-Girl
Girl-Boy } Permutation of
Boy-Girl } the same thing
Boy-Boy
We can rule out the boy-boy field since there is already the claim that one child is a daughter.
What we are left with is
Girl-Girl
Girl-Boy
That is a 50% chance.
If they claimed that the FIRST child was a girl, then you can include the permutations and assume the 1/3 chance of the second child being a girl.
Problem solved.
Hmmm, the more I think about it, the more issues there are with it.
It depends on whether you look at it small scale or large scale.
Small scale it appears to be 50% chance because the birth of one child doesn't affect the other.
However, if you place a limitation on it, and look at it as a large scale model, then the answer is 1/3
For a large scale model you have 100 families.
25 G-G
25 G-B
25 B-G
25 B-B
You know one child is a girl, what are the odds the other child is a girl would be 25/75 (since the B-B are eliminated).
However, this is placing limitations and additional information on the question.
Like was said, small scale and large scale are contradicting each other
1st red. You're missing the fact that there is twice as much chance of a GB combination (as BG also comes into this category)
2nd red. Surely Vice-versa?
3rd red. No. As two - 2 child families have, by definition, 4 children, the chances are that there are going to be 2 of each gender. If family A has (at least) 1 girl, the chances of the other child is a girl is one in 3. ie of the 2 boys and 2 girls, 1 girl is accounted for, leaving 1 girl and 2 boys.
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This is getting ridiculously obtuse. benjer - you were right. Now extend your program to show the percentage of 2 child families who had 2 boys. and you'll find .... well see what you find.
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bugger me that was hard work....
edit. I'm surprised that got through.......
2nd edit ...I'll have to call it a night(sorry) c u in a while
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_ _ _ _ _ _ _ HUBCAPS - 1 REPLATE - 1 REPLIED - 0 BOBCATS - 1 HUNDRED - 0 SARONGS - 0
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Oh good grief.
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NIGHTINGALE
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Suppose I ask the 1/3-ist question: "Do you have at least one girl?" and the parents reply "Yes." We'll call this a "yes" family.
Then I ask: "What is the gender of the other child?"
This question is well-defined if the parents have one boy and one girl, but for the approx. 1/3 of the time that the "Yes" families have two girls, they'll ask what 'other' child you're talking about. You didn't specify a 'first' child such that there can be an 'other' child in this case.
Or to make the point clearer, suppose the second question is: "What is the gender and age of the other child?"
If you asked this question, the parents' response would appropriately be "Uh... actually.. we have two daughters. Which one do you mean?", which is ostensibly them telling you "there is no 'other' child; you didn't specify one to begin with".
The 1/2-ist perspective doesn't suffer this drawback. For the 1/2-ist question: "Think of which of your kids did <totally random action>. Is this kid a girl?" (e.g. "Think of which of your kids you saw chewing bubblegum last. It is a girl?", or "Which kid do you have with you? Is it a girl?", etc.) and they answer 'yes'.
Now you have a well-defined 'other' in all contexts, as well as the condition statement being satisfied.
And since families with two girls will be "Yes" families twice as often than 1-boy 1-girl families (per Bayes' rule) under this scheme, our 1/2-ist philosophy comes by its name rightfully.
My $0.02, at any rate.
If you have 2 children, both girls, and 1 of them is a girl, then the 'other' child is also a girl. I really don't see your point.
I have 2 daughters. If someone says to me "Do you have at least 1 daughter?", I say "Yes". If they then ask what the gender of my 'other' child is, I don't say "what other child?"
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_ _ _ _ _ _ _ HUBCAPS - 1 REPLIED - 0 BOBCATS - 1 HUNDRED - 0 SARONGS - 0
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I'm bringing some catnip (with no additives!) .
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This teaser is about 4 years old now. It was resurrected about a year ago as: http://brainden.com/...8--/' . On the last couple of pages, you'll see there are programs which come to the same conclusion as benjer3's. (including a rare excursion into programming by one Mr F.Pig
)***************Sorry, the above link seems to have got corrupted between copying and pasting. Try
, you cunning minx, but that's just how I found you out in the first place 
. plus the catnip.
Ambrose Bierce was onto something..... 
Four Letters ROLLO
in Games
Posted
CURB