Salesman in a Square in New Logic/Math Puzzles Posted April 8, 2018 · Report reply 13 hours ago, DejMar said: Hide contents My intuitive placement and path of the cabins would be thus: Let the vertices of the square be A, B, C, D with the diagonals being AC and BD. Let the first cabin [a] be at point A. Let the second cabin be a walk of 1 mile from A along the diagonal AC.Let the third cabin [c] be perpendicular to diagonal AC on side CD.Let the fourth cabin [d] be at or on toward point D at no less distance than point C from cabin ;this should be approximately 0.4 miles distant from cabin [c].Let the fifth cabin [d] be at point C.Let the sixth cabin [e] be at point B.Finally, a return to the car at cabin [a], point from cabin [e] A requires another walk of 1 mile.Accumulative walk is approximately 4.8 miles. Not a bad result. Spoiler The locations (four corners, side and circular arc) are all correct. But adjusting the last two a bit, and changing the first cabin, in order to alter the sequence, the distance can exceed 5.