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Posts posted by bonanova


On 12/15/2017 at 8:10 AM, Pickett said:Best answer so far. Can you do exactly one (1) better?.
22 hours ago, BMAD said:how are we defining touching?
Touching refers to red squares, which do not touch: Every point in the plane belongs to at most one red square.
Donald Cartmill:
Spoilernew answer is 8 ; 1 beneath the gray but rotated 60 degrees ,a 2nd above the gray but rotated 30 degrees. Red squares cannot have points in common. 4 more one at each corner= 6 ,however if you rotate the top two corner reds away from center you can place a red with one corner touching the gray at the mid point of the top side of the gray. You can do the same at the bottom two corner "Reds",rotating them outward and then placing the 8th red with a corner touching the gray at the midpoint of the grays' bottom side. If the red over gray is considered to be touching (yes) the red beneath the gray then the answer is 7
Can you do exactly one (1) better?.


3 hours ago, CaptainEd said:“Touch” elucidation question: Does the gray square overlap red squares? Or can only edges overlap? Or can they only share single points?
Gray squares overlap red squares but the overlap need not involve a corner (e.g. aligned centers and rotated 45 degrees.) Overlap can be any positive amount, from full overlap to a small portion of a corner, but positive  not zero.
And of course there is no Red/Red overlap; red squares do not touch.

The area of the triangle is 1. What is the area of the white portion?

I randomly drew some squares on a sheet of paper and colored them red. Then I drew a gray square of equal size and counted the number of red squares it touched. Not very many. I forget the actual number, might have been 4 or 5. But it made me wonder: What is the largest number of red squares that a single gray square can touch?
The squares are all of equal size and none of the red squares touch each other.

Possibly ... ?
SpoilerA liar.

Looks like
SpoilerIf one is ahead of the other two, there are exactly three ducks.
(To fit the given conditions all must be in a row with no two beside each other.) 
17 hours ago, BMAD said:I know what you mean but I don't think it is worded it right
You're right. I botched it. rodomac's wordless pics were in my mind, but they never made it to the keyboard.
Spoiler"any part of" should be "all of."

SpoilerYou arrange with a friend to tell you the sum of three numbers, one each of which will be told him by the group. No mention is made to the friend of the meaning of the numbers. You each then tell the friend your salary, and you divide the sum the friend tells you by 3. You thus determine the average without telling one another your salaries.

SpoilerThe Brooklynbound train arrives, each hour, exactly 54 minutes after the Bronxbound train. The time intervals determine the destination probabilities, and they are in the ratio of 54:6 = 9:1, favoring Brooklyn.

SpoilerYou tilt the glass as far as you can without spilling any water. If water still touches any part of the bottom of the glass, the glass is more than half full. Otherwise less. If the water just touches the edge of the bottom, it's exactly half full.

Maybe, maybe not.
SpoilerTaking the natural log of both sides yields
(1/x) ln(x) = (x) ln(x)
ln(x) [1/x + x] = 0
This has solutions
ln(x) = 0 ==> x = 1
And
1/x + x = 0 ==> x^{2} + 1 = 0 ==> x = (+/) i
So there are three solutions, one of which is real.

On 9/13/2017 at 2:21 AM, bonanova said:I, as well, stand by my answer.
Spoiler OP does not say "on" an ellipse.
 Nor a particular ellipse.
To finish my proof, fasten a string to the foci that loops a pencil at the ellipse point.
Draw an ellipse.Caveat:
SpoilerThe OP could be more definitive.
Take, for example, the phrase "that you know a foci is located at (0,0)."
My interpretation would be rock solid if OP said
How many points would you need to have to uniquely determine an ellipse "that has a focus located at (0,0)"?

It would be dead wrong if OP said
There is an ellipse that has a focus at (0,0).
How many points on that ellipse do you need to draw that ellipse?

To clarify. You don't have any of these abilities:
 Make a line segment of equal length to another segment, or equivalently make equallyspaced pairs of points. (You don't have a pair of dividers.)
 Make a line segment that is parallel to another line (segment).
 Make an arc. (You don't have a compass.)
But you do have the equivalent of a straightedge.

Don't see how it matters, unless ...
SpoilerYou do more than "take a shot."
If you keep shooting until someone is killed, then just don't be the first to shoot.
Why? Because a bullet in either of chambers 1 and 6 will kill the first shooter.
The other four shooters have a 1/6 death probability. 
SpoilerAs I understand these things, he can't escape a black hole that way.
The reason is that as objects enter the vicinity of a black hole (approach it, but before they cross the event horizon) they get spaghettified. They lose their structural integrity. If Superman had crossed the event horizon, the "front" of the spaceship would already have already been ripped from its "back" apart. Sadly, our super hero would also have suffered the same fate. Even if his super powers allow him to stay in one piece, his space ship would offer him no assistance in exiting the event horizon. He would have to do that on his own.
And, the OP asks whether the space ship would help him exit. The answer is, it wouldn't.
As I understand what happens, to ordinary matter, is the difference in gravitational attraction experienced by the near and far portions of objects is so extreme that they are pulled apart, like so much taffy, but worse  torn apart, almost at the molecular level. That damage would be irreparable. The space ship would disintegrate.

Thanks to araver for the game.
With a full (original) compliment of players the game would have unfolded very differently, even with a lucky lynch.

I'm headed to bed (US EDT). I'll read my obit when I wake up.
I hope something kind is said ...
I'm wondering ... has a player ever been BOTH of the first two kills before? Poor Aura

3 hours ago, nana77 said:Is there time to get the new actions in?
I am suspicious of Flame for pushing the tie d1. Even though the results were nice. And I am wary of Gavin. Plas scores some goodie points for his plan. idk about Bona.
I'm in. I'm changing my block now. (said the soldier willing to die for the cause.)

56 minutes ago, flamebirde said:Bona, who did you claim?
You mean which Goodie? I didn't.
But if the list of names were alphabetized I'd be at the tail end.
Thus I'm a non factor at this point. 
So ... if Dolores or Hector is still around ... then ... grab the gun and get it done?
Gav and I have claimed goodie roles. I don't know what (1 of 2 roles) Nana has claimed.
Flame and plas: just need one of you to claim and it's done. Wow.

11 hours ago, plasmid said:Considering that the only role with a color in its Role Description is the Man in Black, you might want to try another hint.
bonanova < (goodie color)

59 minutes ago, gavinksong said:On the other hand, I would really like to hear from bonanova.
Well other than the reference to my color, it's so early in the game I don't know what else to allude to.
That said, there are so many goodies, it seems likely one of us will swing tomorrow morning. Sad.

Agree Phil should post.
Also the other analyses are good reading; I'd like to see more.As for myself: I like my color.
1. Gavinksong  voting for Flamebirde
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3. Nana77  voting for plasmid
4. plasmid  voting for phil
5. phil1882
6. bonanova  voting for phil
3color cube
in New Logic/Math Puzzles
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I'll just point out the interesting fact that with a tetrahedron, saying "two sides white" exhausts all permutations, since all pairs of sides share an edge. But with the cube this is not the case. So, I'm wondering what "patterns" is intended to mean: combinations? or permutations?