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Showing content with the highest reputation on 02/10/15 in all areas
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k-man always has such elegant solutions to these problems. I'm sorry but I couldn't contain myself. Thanks, gavinksong, but the real credit should be given to BMAD for posting these great puzzles.1 point
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Is this claim for any nxm table or only when n = m ? For any nxm. I don't have a rigorous proof, but I think it would go along these lines...1 point
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Using the interpretation of "crossing" as "having a common point with"...1 point