[rookie1ja]

No. 2 - Back to the Cryptograms and Algebra Puzzles
Replace the same characters by the same numerals so that the mathematical operations are correct.

IFIB - EBG = CEH
   -	 -	 +
CCE  /  GD =  FE
------------------------
EFF  + EED = CBA

Spoiler for Solution:

No. 2 - solution
A=9, B=7, C=8, D=6, E=4, F=3, G=2, H=5, I=1

1317 - 472 = 845
   -	 -	 +
 884  /  26 =  34
------------------------
 433  + 446 = 879

[BoilingOil]

Quote

No. 2 - Back to the Cryptograms and Algebra Puzzles
Replace the same characters by the same numerals so that the mathematical operations are correct.
IFIB - EBG = CEH
- - +
CCE / GD = FE
------------------------
EFF + EED = CBA

From IFID - CCE = EFF follows that I = 1
From CCE / GD = FE follows that D x E must be xE, which limits the possibilities to E = 4 and D = 6, or E = 5 and D = 3, 7 or 9 (other options not possible, because 1 is already in use)
If we assume E to be 4, we get 4BG - G6 = 446, which would imply G = 2, and therefor B = 7, and because of 1F17 - 472 = C4H, H would become 5.
C45 + F4 = C7A would then imply that A = 9, and from 4FF + 446 = C79 would follow that F = 3 and C = 8

884 / 26 = 34, which covers the CCE / GD = FE line perfectly in accordance with all the above.

1317 - 472 = 845
- - +
884 / 26 = 34
----------------
433 + 446 = 879

A = 9, B = 7, C = 8, D = 6, E = 4, F = 3, G = 2, H = 5, I = 1

Since this solution fits perfectly, I see hardly a need to try the E = 5 option. Hardly reasonable to expect that there are two valid solutions to this type of puzzle.

Thanx for having this section, Rookie. I've always loved this kind of puzzles


BoilingOil