bonanova Posted November 13, 2014 Report Share Posted November 13, 2014 Quote Link to comment Share on other sites More sharing options...
0 Pickett Posted November 13, 2014 Report Share Posted November 13, 2014 6: no - after putting a triangle in each corner (which must be done to fill the corners), you must put another triangle with its edge along the edge of the board, which then leaves you with 3 separated hexagons left7: no - 28 hexagons on the board is not divisible by 3 8: no - again, after putting the triangles in the corners, you will end up with 3 hexagons that left over that can't be covered with a triangle 9: yes I can give more detail if needed for any of these...but the OP didn't actually ask for "why or why not..." so... Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted November 14, 2014 Author Report Share Posted November 14, 2014 I'm trying to think of a rule for this. Quote Link to comment Share on other sites More sharing options...
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