Guest Posted October 25, 2011 Report Share Posted October 25, 2011 A 2x3 rectangle and a 3x4 rectangle are contained within a square without overlapping at any interior point. The sides of the square are parallel to the sides of the two rectangles. What is the smallest possible area of the square? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 25, 2011 Report Share Posted October 25, 2011 25 units squared. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 25, 2011 Report Share Posted October 25, 2011 Define "overlap". Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 Overlap = don't share the same space Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 18, of course Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 18, of course 3 is the common side, other side is 2+4=6 Therefore, 3x6=18 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 (edited) Missed the point. 6x3 is a rectangle, not a square. So, 18 is not the answer. Not that simple Edited October 26, 2011 by akgrover Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 25 units squared. That's right. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 If one thinks of these as solids, then placing them on a surface and putting one against the other gives smallest occupying space.would be the smallest square that can contain both rectangles in a unique space. Thus the minimum square is 5X5 and CocoChanel555 is correct - 25 squared units is smallest possible square. If this is not the answer, then something is omitted in the question Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 26, 2011 Report Share Posted October 26, 2011 Define "overlap". If you can't put the 2x3 inside the 3x4 then the minimum size square is 5 x 5 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted November 14, 2011 Report Share Posted November 14, 2011 25 units square Quote Link to comment Share on other sites More sharing options...
Question
Guest
A 2x3 rectangle and a 3x4 rectangle are contained within a square without overlapping at any interior point. The sides of the square are parallel to the sides of the two rectangles. What is the smallest possible area of the square?
Link to comment
Share on other sites
10 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.