Guest Posted October 20, 2010 Report Share Posted October 20, 2010 A box with dimensions of 200x200x200 cm has some chocolates in it. the chocolates take up 54 percent of this volume. exactly half of the chocolates have the dimensions 2x3x4 cm (we'll call these chocolates A ) the other half have the dimensions 3x4x5 cm (we'll call these chocolates B ) How many chocolates are in the box? what is the maximum number of chocolates that can fit in the box using a "Chocolates A - Chocolates B" ratio of 2:3 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 2/5 of box = 1728000 has 72000 As (72000x24) 3/5 of box = 2592000 has 43200 Bs (43200x60) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 2/5 of box = 1728000 has 72000 As (72000x24) 3/5 of box = 2592000 has 43200 Bs (43200x60) you haven't answered the question. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 A box with dimensions of 200x200x200 cm has some chocolates in it. the chocolates take up 54 percent of this volume. exactly half of the chocolates have the dimensions 2x3x4 cm (we'll call these chocolates A ) the other half have the dimensions 3x4x5 cm (we'll call these chocolates B ) How many chocolates are in the box? what is the maximum number of chocolates that can fit in the box using a "Chocolates A - Chocolates B" ratio of 2:3 I keep coming up with a fractional answer. Is that what you were looking for? I also read the question literally, as in half of the chocolates are A, and have are B, as opposed to half of the chocolate is from A, and half from B. This would imply that there are no fractions... Here are my equations 24a + 60b = 4,320,000 a = b 84a = 4,320,000 which would give me 102857.1428571429 chocolates in the box. Did I do something wrong? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 I keep coming up with a fractional answer. Is that what you were looking for? I also read the question literally, as in half of the chocolates are A, and have are B, as opposed to half of the chocolate is from A, and half from B. This would imply that there are no fractions... Here are my equations 24a + 60b = 4,320,000 a = b 84a = 4,320,000 which would give me 102857.1428571429 chocolates in the box. Did I do something wrong? Thats right! I couldn't be bothered to find a whole number and then back track though the equation, so i just used random numbers for the dimensions. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 Thats right! I couldn't be bothered to find a whole number and then back track though the equation, so i just used random numbers for the dimensions. erghhhhhhhh........................... your laziness makes my head hurt... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 erghhhhhhhh........................... your laziness makes my head hurt... ha ha sorry about that, If you want a real challenge. why not try my "bomb, code, password" puzzle. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 (edited) Dude something is wrong with the numbers...here is my calculation Box size = 8,000,000 cm^3 54% of box = 4,320,000cm^3 A size = 24cm^3 B size = 60cm^3 (quick notice : B = 2.5 A) Set X As number of A Chocolates Set Y As number of B Chocolates Set A As size of A chocolate Set B As size of B chocolate xA + yB = 4,320,000 cm^3 (we know that for each B we have 2.5 A's) so xA + 2,5xA = 4,320,000 cm^3 24x+60x = 4,320,000 cm^3 84x = 4,320,000cm^3 x = 4,320,000/84 <--- and here is the problem.The devision is not a valid number 51,428.5714 (for chocolates ! ) Unless i have made a mistake i cannot spot , i guess you made it up but didn't check it or that you gave accidentaly wrong numbers. I confident i didn't made wrong be couse i took the hard way,too: WAY 2: We can assume that the box fits 72000 B OR 180000 A With the logic that if we remover some B chocolates of the total they can fit in the 54% of the box...and replace them with A chocolates, and then add the B we removed and the A we replaced, we would get how much chocolates we have (only if the chocolates we removed are the same number of chocolates A becouse you said the numbers are 50% B 50% A) So i did this: Each time i remove a number from 72000(72000 - x = y) and then i do this (y*2,5 = p ) It becomes clear that when x gets higher p gets lower.Example: (remember we need x = p) 72000-36000 = 36000 , 36000*2.5 = 90000 (36000 | 90000 ) 72000-48000 = 24000 , 24000*2.5 = 60000 (48000 | 24000 ) 72000-50000 = 22000 , 22000*2.5 = 55000 (50000 | 55000 ) 72000-51420 = 20580 , 20580*2,5 = 51450 (51420 | 51450 ) <--We see that the answer is about here... witch actually matches the first way becouse the division 4,320,000/84 is about 51,428.5714 But anyway lets say that 51,428.5714 + 51,428.5714 = 102,857.1428 Well with these numbers i'm not quite in the mood to find the second question! Edited October 20, 2010 by Tsopi Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 20, 2010 Report Share Posted October 20, 2010 Dude something is wrong with the numbers...here is my calculation Box size = 8,000,000 cm^3 54% of box = 4,320,000cm^3 A size = 24cm^3 B size = 60cm^3 (quick notice : B = 2.5 A) Set X As number of A Chocolates Set Y As number of B Chocolates Set A As size of A chocolate Set B As size of B chocolate xA + yB = 4,320,000 cm^3 (we know that for each B we have 2.5 A's) so xA + 2,5xA = 4,320,000 cm^3 24x+60x = 4,320,000 cm^3 84x = 4,320,000cm^3 x = 4,320,000/84 <--- and here is the problem.The devision is not a valid number 51,428.5714 (for chocolates ! ) Unless i have made a mistake i cannot spot , i guess you made it up but didn't check it or that you gave accidentaly wrong numbers. I confident i didn't made wrong be couse i took the hard way,too: WAY 2: We can assume that the box fits 72000 B OR 180000 A With the logic that if we remover some B chocolates of the total they can fit in the 54% of the box...and replace them with A chocolates, and then add the B we removed and the A we replaced, we would get how much chocolates we have (only if the chocolates we removed are the same number of chocolates A becouse you said the numbers are 50% B 50% A) So i did this: Each time i remove a number from 72000(72000 - x = y) and then i do this (y*2,5 = p ) It becomes clear that when x gets higher p gets lower.Example: (remember we need x = p) 72000-36000 = 36000 , 36000*2.5 = 90000 (36000 | 90000 ) 72000-48000 = 24000 , 24000*2.5 = 60000 (48000 | 24000 ) 72000-50000 = 22000 , 22000*2.5 = 55000 (50000 | 55000 ) 72000-51420 = 20580 , 20580*2,5 = 51450 (51420 | 51450 ) <--We see that the answer is about here... witch actually matches the first way becouse the division 4,320,000/84 is about 51,428.5714 But anyway lets say that 51,428.5714 + 51,428.5714 = 102,857.1428 Well with these numbers i'm not quite in the mood to find the second question! yeah you were right. caprirs302 got there first. and yes i was too lazy to find a whole number and trace it back to get proper dimensions. lol oh well. well done all the same. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 21, 2010 Report Share Posted October 21, 2010 ha ha sorry about that, If you want a real challenge. why not try my "bomb, code, password" puzzle. Your number pattern puzzles go "way out there." I really like to solve things that involve a bit more logic than searching through endless possibilities..... But thanks though Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 21, 2010 Report Share Posted October 21, 2010 Your number pattern puzzles go "way out there." I really like to solve things that involve a bit more logic than searching through endless possibilities..... But thanks though thats ok. i'm not smart enough to come up with something really logical. lol Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 21, 2010 Report Share Posted October 21, 2010 what is the maximum number of chocolates that can fit in the box using a "Chocolates A - Chocolates B" ratio of 2:3 70174 A + 105261 B Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 21, 2010 Report Share Posted October 21, 2010 70174 A + 105261 B No idea. but your probably right. well done. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted October 21, 2010 Report Share Posted October 21, 2010 yeah you were right. caprirs302 got there first. and yes i was too lazy to find a whole number and trace it back to get proper dimensions. lol oh well. well done all the same. Lol thanx you confirm that lol.I was about to bang my head over the wall becouse i couldn't come up with a propel number and i was like:Ohhh what the F*** do i do wrong? Quote Link to comment Share on other sites More sharing options...
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A box with dimensions of 200x200x200 cm has some chocolates in it.
the chocolates take up 54 percent of this volume.
exactly half of the chocolates have the dimensions 2x3x4 cm (we'll call these chocolates A )
the other half have the dimensions 3x4x5 cm (we'll call these chocolates B )
How many chocolates are in the box?
what is the maximum number of chocolates that can fit in the box using a "Chocolates A - Chocolates B" ratio of 2:3
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