Guest Posted August 18, 2010 Report Share Posted August 18, 2010 (edited) If you take four dice and roll them, there is a good chance that you will be able to make seven from the resulting numbers. Question is though, can you solve the harder ones? Regardless of that here's a couple for you to solve here. 6 6 6 4. 1 1 1 1. (You can use ANY mathematical operator.) Edited August 18, 2010 by Links1219955 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 6+(6/6)^4 = 7 (1+1+1)!+1 = 7 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 (edited) Are you permitting mathematical functions as operators? Edited August 18, 2010 by Dej Mar Quote Link to comment Share on other sites More sharing options...
0 plainglazed Posted August 18, 2010 Report Share Posted August 18, 2010 6 + 4(6-6) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 (edited) So I grabbed some dice to waste some time at work and am stuck on this: 2 2 4 5 Help! [spoiler=Nevermind. Got it ](5-2)!/2 + 4 Edited August 18, 2010 by Tuckleton Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 So I grabbed some dice to waste some time at work and am stuck on this: 2 2 4 5 Help! [spoiler=Nevermind. Got it ](5-2)!/2 + 4 (2 MOD (2+4))+5 (I try to keep the digits in the sequence given. More of a challenge.) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 i got n easy 1......... 2*(2+4)-5=7 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 (sqrt2*sqrt2)+5!-4! i got n easy 1......... 2*(2+4)-5=7 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 (sqrt2*sqrt2)+5!-4! I assume you meant (√2 × √2) + 5!/4! 5!-4! = 120 - 24 = 96 5!/4! = 5 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 Good to see people like the puzzle ANY mathematical thing you can think of. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 ⌈((6 / 4)/6)+6⌉ (use of the celing function) Still working on the 1111.... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 18, 2010 Report Share Posted August 18, 2010 Having trouble with 2222 and 1112. Any thoughts? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 19, 2010 Report Share Posted August 19, 2010 Having trouble with 2222 and 1112. Any thoughts? ⌈(!(2+2))/2⌉+2 The subfactorial of 4 is 9. 9/2 = 4.5. The ceiling of 4.5 is 5. 5 + 2 = 7. (1+1)# + ⌈1/2⌉ The primorial of 2 is 6. The ceiling of 1/2 is 1. 6+1 = 7. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 19, 2010 Report Share Posted August 19, 2010 Perfect, thanks! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted August 20, 2010 Report Share Posted August 20, 2010 (edited) I thought of this game while rolling four dice aimlessly. Then I remembered an advertisement that I had seen which goes something like this: *Lots of brilliant looking smart people in a large semicircle theater kind of thing* *Seven and Three are in large numbers on the flat wall* *Suddenly one of them goes "Seven!" and then another goes "SEVEN!" and the narrator goes "Here at (car company) we have decided that seven is definatly more, than three. So that why we are giving you our seven year guarantee..." In short a couple of people shout SEVEN! In an extremely epic manner. Edited August 20, 2010 by Links1219955 Quote Link to comment Share on other sites More sharing options...
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Guest
If you take four dice and roll them, there is a good chance that you will be able to make seven from the resulting numbers. Question is though, can you solve the harder ones?
Regardless of that here's a couple for you to solve here.
6 6 6 4.
1 1 1 1.
(You can use ANY mathematical operator.)
Edited by Links1219955Link to comment
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