Guest Posted May 27, 2010 Report Share Posted May 27, 2010 1,2,3,13,16,19,22,179,201,223,245... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 1,2,3,13,16,19,22,179,201,223,245... 2233 2478 2723 2968 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 Is the answer 2945...3190...3435 The formula is 245n + X Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 the answer is 267.. the first 3 number 1,2,3 = plus 1 for 3 numbers 13,16,19,22 = plus 3 for 4 numbers 179,201,223,245 = plus 22 for 5 numbers but only 4 are given. juz do 245+22= 267 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 i mean the next number is 267 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 next number after 267 may be 267*13+22 i.e last number * position in the sequence + difference of the last subseq Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 27, 2010 Report Share Posted May 27, 2010 (edited) The correct number has been found but the reason was just a trivial coincidence. So here is an extended version: 1,2,3,13,16,19,22,179,201,223,245,267,289,311,56123,52518... I will add a hint later if no one gets it. Edited May 27, 2010 by psychic_mind Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 28, 2010 Report Share Posted May 28, 2010 The correct number has been found but the reason was just a trivial coincidence. So here is an extended version: 1,2,3,13,16,19,22,179,201,223,245,267,289,311,56123,52518... I will add a hint later if no one gets it. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 28, 2010 Report Share Posted May 28, 2010 Is the final number decrementing, or is that a typo? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 28, 2010 Report Share Posted May 28, 2010 (edited) Is the final number decrementing, or is that a typo? Ah sorry. That should be: 1,2,3,13,16,19,22,179,201,223,245,267,289,311,56163,52518... They continue to increment in 355s to at least 100,000 (I have used a computer to generate the sequence). However, this does not describe the sequence. It so happens that the sequence groups into arithmetic progressions but what actually is it? Edited May 28, 2010 by psychic_mind Quote Link to comment Share on other sites More sharing options...
0 Pickett Posted May 28, 2010 Report Share Posted May 28, 2010 Ah sorry. That should be: 1,2,3,13,16,19,22,179,201,223,245,267,289,311,56163,52518... They continue to increment in 355s to at least 100,000 (I have used a computer to generate the sequence). However, this does not describe the sequence. It so happens that the sequence groups into arithmetic progressions but what actually is it? Still seems like you mis-typed the last number or two...because that still shows it decrementing. Is it supposed to be: 56163, 56518? or 52163, 52518? Also, I just wanted to verify that it increments by 355 after that? not 311? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted May 28, 2010 Report Share Posted May 28, 2010 Still seems like you mis-typed the last number or two...because that still shows it decrementing. Is it supposed to be: 56163, 56518? or 52163, 52518? Also, I just wanted to verify that it increments by 355 after that? not 311? That's strange I'm sure I changed it. 1,2,3,13,16,19,22,179,201,223,245,267,289,311,52163,52518 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 2, 2010 Report Share Posted June 2, 2010 No one has this yet. Time for a hint. 1,1,1,4,5,6,7,57,64,71,78,85,92,99,106,113 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 6, 2010 Report Share Posted June 6, 2010 Showed this to the guys at school and they couldn't find it out, just like me and apparently just like everyone else who looked at this topic. Can this sequence be defined by a function such as f(x)= x+2/x+3 or something like that? Or is it defined by a set of rules like "Add one, then multiply by two, the add three and so on"? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 6, 2010 Report Share Posted June 6, 2010 ^ I think it's defined by a rule and the sequence depends on the first 2 or maybe even 3 numbers cause the original one is: 1,2,3,13,16,19,22,179,201,223 1,1,1,4,5,6,7,57,64,71,78,85,92,99,106,113 And the other is psych's hint.... Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 6, 2010 Report Share Posted June 6, 2010 There may be a formula but I'm not aware of one. Try playing around with the two sequences. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 6, 2010 Report Share Posted June 6, 2010 (edited) 1,2,3,13,16,19,22,179,201,223,245... ans is 267 explanation: first three are inc by 1 then four entities are by 3 then five entities shud be inc by same amount which is 22 hence ans ll be 245+22=267 here d amt by which the entities r inc doesnt matter Edited June 6, 2010 by onkar Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 6, 2010 Report Share Posted June 6, 2010 ans is 267 explanation: first three are inc by 1 then four entities are by 3 then five entities shud be inc by same amount which is 22 hence ans ll be 245+22=267 here d amt by which the entities r inc doesnt matter Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 7, 2010 Report Share Posted June 7, 2010 ans is 267 explanation: first three are inc by 1 then four entities are by 3 then five entities shud be inc by same amount which is 22 hence ans ll be 245+22=267 here d amt by which the entities r inc doesnt matter No sorry, that isn't it. I think you need to consider both sequences together in order to figure it out. I didn't want to post both in the OP in case it was too easy. Seems I was wrong. It's hard to judge the difficulty of your own puzzles. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted June 9, 2010 Report Share Posted June 9, 2010 The sequence increases so that each number is the numerator of a fraction giving a closer approximation to Pi. 1/1 2/1 3/1 13/4 16/5 19/6 22/7 and so on. Quote Link to comment Share on other sites More sharing options...
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1,2,3,13,16,19,22,179,201,223,245...
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