[Guest]

abc

abc

+abc

-----

bbb

-----

If each letter depicts a single digit(sorry for going against algebraic laws ) can you guess what the values of a, b, and c are?

[Guest]

148+148+148=444

[Guest]

When you need abc to represent a 3 digit number you write them in capitals like this:

ABC

ABC

ABC +

___

BBB

So 3*ABC=BBB right? So A can't be 0 (unless all of them are zeros then 000+000+000=000 which could be an answer) So A can be either 1, 2 or 3.

300A + 30B + 3C = 100B +10B + B

300A + 3C = 81B

100A + C = 27B

100A + C = A0C

A0C has to be divisible by 9, so according to the laws of 9 divisibility A+C can be divided by 9, A as we said before can only be 1, 2 or 3 (otherwise the sum would be larger than 1000) So C can be 8, 7 or 6.

So here are the possibilities:

(A,B,C)

(1,B,8)

(2,B,7)

(3,B,6)

The only pair that have an integer result for B in 100A + C = 27B is 1 and 8 so

A=1

B=4

C=8

148*3=444

[Guest]

148?

[Guest]

[spoiler=Ther answer is............... ]

A=1

B=4

C=8

[Guest]

B=1, 111/3=037 X

B=2, 222/3=074 X

B=3, 333/3=111 X

B=4, 444/3=148 O

B=5, 555/3=185 X

B=6, 666/3=222 X

B=7, 777/3=259 X

B=8, 888/3=296 X

B=9, 999/3=333 X

So this ensures that it's 148+148+148=444