[rookie1ja]

1996 - Back to the Number Puzzles
Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:
29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.
All the numerals must be used in the given order (each just once) and without turning upside down.

Spoiler for Solution:

1996 - solution
 1996-solution.gif (4.62K)
Number of downloads: 5223
I used [brackets] as the symbol for root.

[onyx_sisco]

I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

[mdsl]

Quote

I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

You forgot a root:

-1 + root(9) + root[root(9)^6]
=-1 + 3 + root[3^6]
=-1 + 3 + 3^3
=-1 + 3 + 27
=29

[Bob Coolio]

I get it. That is so awsome

[ash013]

[quote name='rookie1ja' date='Mar 30 2007, 08:09 PM' post='106']
1996 - Back to the Number Puzzles
Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:
29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.
All the numerals must be used in the given order (each just once) and without turning upside down.

For 32 there is another way to do it:
-1+[9]x9+6=32
For 38:
19/[9]/6=19x6/[9]=38,
actualy is the same,just 1 step before the shown equation.

[brian.w.hoffman]

rookie1ja, on Mar 30 2007, 01:09 PM, said:

1996 - Back to the Number Puzzles
Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:
29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.
All the numerals must be used in the given order (each just once) and without turning upside down.

Spoiler for Solution:

1996 - solution
1996-solution.gif
I used [brackets] as the symbol for root.

another solution for 76:
91 - (9+6) = 76
91 - 15

and for 35:

[[9]6] + 9 - 1 = 35
[3^6] + 9 - 1
3^3 + 9 - 1
27 + 9 - 1 = 35

[tickytock]

brian.w.hoffman, on Jan 5 2009, 08:53 AM, said:

another solution for 76:
91 - (9+6) = 76
91 - 15

and for 35:

[[9]6] + 9 - 1 = 35
[3^6] + 9 - 1
3^3 + 9 - 1
27 + 9 - 1 = 35

numbers need to be in 1996 order....

[vij]

tickytock, on Mar 5 2009, 06:06 AM, said:

numbers need to be in 1996 order....

 number_puzzle_1996.JPG (12K)
Number of downloads: 2