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1996

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1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

This old topic is locked since it was answered many times. You can check solution in the Spoiler below.

Pls visit New Puzzles section to see always fresh brain teasers.

1996 - solution

post-2-1175278139_thumbgif

I used [brackets] as the symbol for root.

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Posted · Report post

I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

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I get all of them except the answer 29... please explain. It would end up being -1+3 + (3^6) which is 2 + 729 = 731 The only way it would work if is 2 is added to 27. To get 27 the multiples are 3x3x3 and I can't figure that out with 9 and 6.

You forgot a root:

-1 + root(9) + root[root(9)^6]

=-1 + 3 + root[3^6]

=-1 + 3 + 3^3

=-1 + 3 + 27

=29

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Posted · Report post

I get it. That is so awsome :)

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Posted · Report post

1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

For 32 there is another way to do it:

-1+[9]x9+6=32

For 38:

19/[9]/6=19x6/[9]=38,

actualy is the same,just 1 step before the shown equation.

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Posted · Report post

1996 - Back to the Number Puzzles

Using the numerals 1, 9, 9 and 6, mathematical symbols +, -, x, :, root and brackets create the following numbers:

29, 32, 35, 38, 70, 73, 76, 77, 100 and 1000.

All the numerals must be used in the given order (each just once) and without turning upside down.

1996 - solution

post-2-1175278139_thumbgif

I used [brackets] as the symbol for root.

another solution for 76:

91 - (9+6) = 76

91 - 15

and for 35:

[[9]6] + 9 - 1 = 35

[3^6] + 9 - 1

3^3 + 9 - 1

27 + 9 - 1 = 35

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Posted · Report post

another solution for 76:

91 - (9+6) = 76

91 - 15

and for 35:

[[9]6] + 9 - 1 = 35

[3^6] + 9 - 1

3^3 + 9 - 1

27 + 9 - 1 = 35

numbers need to be in 1996 order....

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Posted · Report post

numbers need to be in 1996 order....

post-14049-1236310732.jpg

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