# littlej

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## littlej's Activity

1. littlej added a post in a topic

2. littlej added a post in a topic

We should add a couple twists to this puzzle:
1) How many different unique solutions exist?
2) Can you determine a set of positive integer numbers that makes a unique solution? If not, what is the minimum sum required to form a unique solutions (i.e. all add to 50 instead of 25).
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3. littlej added a post in a topic

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8. littlej added a post in a topic

I should add that I do not know the answer to #4, thus the (Impossible?) tag.
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9. littlej added a topic in New Logic/Math Puzzles

How many bits are required to represent the result of the operations below on a positive integer 'm' that contains 'n' bits:

1) (Easy) 2*m
2) (Medium) m*m
3) (Hard) m^m
4) (Impossible?) m!

Good luck.
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10. littlej added a post in a topic

Neat Thanks. Do you interpret the question differently?
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11. littlej added a post in a topic

I'm not sure I understand what you are mean - the question is about circles, not hexagons. There is no possible way to fill up all white space. I believe there will be conditions where it is optimum not to put the circles into the recesses. You are limited to 1 circle every two recesses doing this - try it out. You will see the effect as the size of the smaller circles decrease.

A note about the 'least number of circles': I assumed that he just made a typo - it would be fairly obvious that 1 is the least number of circles as long as it is smaller.
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12. littlej added a post in a topic

He is looking for a generalized solution.

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13. littlej added a post in a topic

Wow, yes it does make sense. Thanks.
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15. littlej added a post in a topic

Wouldn't you need Math.pow(i,j) ^ Math.pow(i,j) (i.e. ^ instead of *)? the result is extremely large (a much large integer than I can handle in my programming language).

There has to be a different approach...
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