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Guest Message by DevFuse
 

nikolas

Member Since 26 Feb 2014
Offline Last Active Mar 06 2014 05:02 PM
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Posts I've Made

In Topic: Find The Hidden List

28 February 2014 - 12:45 AM

many gredits to all of you and fabpig!


In Topic: Find The Hidden List

26 February 2014 - 05:00 PM

@fabpig Ohh i see, no there will be only 5 lists!

Hint: its 5 lists and only no matter how many elements you have, number 5 plays a role!


In Topic: Find The Hidden List

26 February 2014 - 03:15 PM

Spoiler for bananovas thoughts reply


In Topic: Find The Hidden List

26 February 2014 - 02:45 PM

@fabpig the numer of elements each list contains is n(variable). In this case n=5, and n>=3 always because of the number of permutations. e.g. for n=2, n!=1*2=2<5, but 3!=1*2*3=6>5 and as a result we can have the 5 lists.