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Guest Message by DevFuse
 

jmaurier

Member Since 20 Dec 2012
Offline Last Active Dec 20 2012 09:40 AM
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Posts I've Made

In Topic: Weighing in a Harder Way

20 December 2012 - 09:37 AM

minimum 3 max 6 (If you are splitting into 3 piles each time).

 

incase you don't know: "!=" means "not equal"

 

BEST CASE = 3 tries

1)if A=B then the coin is in C. Split C into three piles (again A,B,C)

2)if A=B then the coin is in C again. Split C into the three last coins.

3)if A=B then C is the coin.

 

WORST CASE = 6 tries

1)A!=B   (piles of 9)

2)Now test A and C

if A=C then split B into ABC

if A!=C then split A into ABC

3)A!=B   (piles of 3)

4)Now test A and C

if A=C then split B into ABC

if A!=C then split A into ABC

5)A!=B   (last 3 coins)

6)Now test A and C

if A=C then B is the coin

if A!=C then A is the coin