If the dark object can pass thru the light object,
are they circle and square or sphere and cube?
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Posted by TimeSpaceLightForce
on 25 April 2013 - 05:25 PM
Posted by TimeSpaceLightForce
on 20 April 2013 - 06:46 PM
I really want to see how good of a code i made.. this is the first one i have ever made, and i feel it is pretty decent. but thats just me. The real test is how long it takes someone to break it. All comments on progress are helpfull and appreciated, thanks!
Posted by TimeSpaceLightForce
on 20 April 2013 - 03:41 AM
Welcome ,have fun!
1, 4, 6, 2, 4, 5, 2, 3, 6, 3;
2, 5, 8, 1, 3, 7, 8, 1, 7, 1;
3, 7, 6, 4, 5, 2;
26 elements could be the alphabet?
1.462452363
2.581378171
3.76452
could be in groups?
Posted by TimeSpaceLightForce
on 19 March 2013 - 06:26 PM
Posted by TimeSpaceLightForce
on 19 March 2013 - 06:01 PM
Posted by TimeSpaceLightForce
on 18 March 2013 - 01:08 PM
Posted by TimeSpaceLightForce
on 07 February 2013 - 06:27 AM
Spoiler for Revised
His neighbor may be highly cagey,
But he's so calm it'll drive you crazy,
You'll sound like a fool,
But he's super cool,
Cuz his symbol is CClF3.
Still doesn't really fit the third line, but it's super cool.
Edit1: Inhaling Freon will make you 'tarded.
Edit: Actually...probably He. I'm gonna rewrite shortly.
Yep, that last one is the one...and it's super freaking climbing up the walls cool...literally ;P.
Down to the last limerick...since I've been in a generous mood...
Spoiler for Final hint...'Without anything' in the most literal sense...without water...air....atmosphere...
*mutters something about wave-particle duality in the background*
Posted by TimeSpaceLightForce
on 31 January 2013 - 04:25 PM
Araver, I guess that means we don't have it right. So I've got a question for you
Spoiler for can we decompose...a set of samples into two sets of different sizes, each of which is balanced? I don't think that's what you were saying, and I don't feel confident about the physics. But If we superimposed and rotated a 2-sample (12,6) with a 3-sample(1,5,9) to create (12 1 5 6 9), we would naturally get 5 and (via complementation) 7.
Posted by TimeSpaceLightForce
on 30 December 2012 - 08:49 AM
the find may be easy as hinted.. just "combination"..so, letters need not ordered.
Posted by TimeSpaceLightForce
on 20 December 2012 - 03:40 AM
What is the product for unanswered = ?
If letters are factors of equations
zero = 0
one = 1
two = 2
three = 3
four = 4
five = 5
six = 6
seven = 7
eight = 8
nine = 9
ten = 10
twelve = 12
fifteen = 15
twenty = 20
thirty = 30
forty = 40
sixty = 60
hundred = 100
thousand = 1000
million = 1000000
billion = 1000000000
note: i got the idea for this puzzle post from X-MAS TREE thread that was unanswered by dtdt..thanks
happy holidays!
Posted by TimeSpaceLightForce
on 17 December 2012 - 07:39 AM
if tilted
8 < 8 11
try lighter
none or one
4 = 4
4 < 4'
if balanced
8 = 8 11
distribute by color
8' 4' = 1 11'' 3
8' 4 < 1' 11'' 3
8' 4 < 1 11'' 3'
8 4 < 1 11'''' 3
8'' 4'' > 1 11 3
Pls. note the previous post..TY
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