nitinjain92

Hii everyone myself nitin and my intrests are in coding algorithms and math puzzles

lim x->∞ ( 1 - 1 / X )X (can be written also as ) = lim x->∞ e( X . log( 1 - 1/X ) ) ( expansion of log ( 1 - 1/X) ) is -1*( 1/x + 1/2x2 + 1/3x3 ..... so on) put this in equation we get = lim x->∞ e( -X *(1/x + 1/2x^2 + 1/3x^3 ..... so on ) ) =lim x->∞ e( -1 *(1 + 1/2x + 1/3x^2 ..... so on ) ) applying limit we get answer = e -1