Jump to content


Welcome to BrainDen.com - Brain Teasers Forum

Welcome to BrainDen.com - Brain Teasers Forum. Like most online communities you must register to post in our community, but don't worry this is a simple free process. To be a part of BrainDen Forums you may create a new account or sign in if you already have an account.
As a member you could start new topics, reply to others, subscribe to topics/forums to get automatic updates, get your own profile and make new friends.

Of course, you can also enjoy our collection of amazing optical illusions and cool math games.

If you like our site, you may support us by simply clicking Google "+1" or Facebook "Like" buttons at the top.
If you have a website, we would appreciate a little link to BrainDen.

Thanks and enjoy the Den :-)
Guest Message by DevFuse
 

Photo
- - - - -

Pouring water I.


  • This topic is locked This topic is locked
48 replies to this topic

#41 Xianpiper

Xianpiper

    Newbie

  • Members
  • Pip
  • 2 posts

Posted 07 August 2008 - 09:46 PM

I have seen a few answers that would work but would waste water.

Here's a method that would require you to waste zero water and allow you to avoid marking or partially filling any bowl.

Place the 3 unit bowl into the 5 unit bowl with the rims in the same plane and fill the 5 unit bowl. This means that you are only filling the space in between the two bowls, thus giving you 2 units because 3 of the 5 units in the 5 unit bowl are taken up by the 3 unit bowl.

Then simply remove the 3 unit bowl and pour the 2 units of water from the 5 unit bowl into the 3 unit bowl.

Then simply repeat the first step filling the 5 unit bowl with the 3 unit bowl placed in it. Then pour the 2 units from the 3 unit bowl into the 5 unit bowl that has the second 2 units in it.

Thus you now have 4 units EXACTLY of water in the 5 unit bowl without wasting any water or partially filling anything.
  • 0

#42 Xianpiper

Xianpiper

    Newbie

  • Members
  • Pip
  • 2 posts

Posted 07 August 2008 - 10:12 PM

I have seen a few answers that would work but would waste water.

Here's a method that would require you to waste zero water and allow you to avoid marking or partially filling any bowl.

Place the 3 unit bowl into the 5 unit bowl with the rims in the same plane and fill the 5 unit bowl. This means that you are only filling the space in between the two bowls, thus giving you 2 units because 3 of the 5 units in the 5 unit bowl are taken up by the 3 unit bowl.

Then simply remove the 3 unit bowl and pour the 2 units of water from the 5 unit bowl into the 3 unit bowl.

Then simply repeat the first step filling the 5 unit bowl with the 3 unit bowl placed in it. Then pour the 2 units from the 3 unit bowl into the 5 unit bowl that has the second 2 units in it.

Thus you now have 4 units EXACTLY of water in the 5 unit bowl without wasting any water or partially filling anything.


This doesn't work because it fails to factor in the volume of water displaced by the actual volume of the 3 litre bowl that you place in the 5 litre bowl.
  • 0

#43 chill4677

chill4677

    Newbie

  • Members
  • Pip
  • 1 posts

Posted 12 September 2008 - 09:00 PM

This came to my mind right away I read all your and didn't see it. It seems so easy I don't trust myself LOL.
You have a 5ltr bowl and a 3 ltr bowl trying to measure out 4ltrs of water.

Why don't you fill the 3ltr bowl up with water. Being careful not to spill.
Pour the water into the 5ltr bowl. Repeat this, fill the 3ltr bowl up again
with water pour all the water that will fit into the 5 ltr bowl. Thus, leaving
1 ltr of water (3+3=6) in the 3 ltr bowl. pour out the 5 ltr bowl of water.
Pour the 1 ltr of water from the 3 ltr bowl into the 5 ltr bowl fill the 3 ltr
bowl with water again and pour this water in the 5ltr bowl adding it to the
1 ltr of water that is already in the 5 ltr bowl. Now we have 4ltrs of water
in the 5 ltr bowl.

  • 0

#44 Wiseoldsnake

Wiseoldsnake

    Newbie

  • Members
  • Pip
  • 1 posts

Posted 13 September 2008 - 04:16 PM

Why not fill both containers fully. 8 liters then pour out half of each 2.5 amd 1.5 respectively then add the 1.5 in the 3 liter to the 2.5 in the 5 liter to equal 4.
  • 0

#45 G Threat

G Threat

    Junior Member

  • Members
  • PipPip
  • 68 posts

Posted 19 September 2008 - 07:51 PM

Why not fill both containers fully. 8 liters then pour out half of each 2.5 amd 1.5 respectively then add the 1.5 in the 3 liter to the 2.5 in the 5 liter to equal 4.



Why not just fill them half full to begin with? Or how about:

fill the 5 pour it into the 3
Dump the 3 and pour the remaining 2 from the 5 into it
fill the 5 and then top up the 3
you should have 4 in the 5 now
  • 0

#46 Josborn94

Josborn94

    Newbie

  • Members
  • Pip
  • 9 posts

Posted 12 October 2008 - 05:43 PM

easy u get a four-litre container and fill ;)
  • 0

#47 cinsatia

cinsatia

    Newbie

  • Members
  • Pip
  • 1 posts

Posted 20 October 2008 - 05:06 AM

(1) fill the 5-Liter bowl
(2) using (1), decant 3L into 3-L bowl; this leaves 2L in the 5-L bowl
(3) in any available ample-sized, "other" container, pour the 2L from the 5-L bowl
(4) reuse water from 3-L bowl into 5-L bowl and fill 5-L bowl to 5L
(5) repeat (2) and (3) to get 4-L in the "other" container

wastes 2L!!!
  • 0

#48 kidsranqe

kidsranqe

    Advanced Member

  • Members
  • PipPipPip
  • 111 posts

Posted 05 November 2008 - 02:54 AM

Spoiler for solution

  • 0

#49 NotSmart

NotSmart

    Newbie

  • Members
  • Pip
  • 1 posts

Posted 11 December 2009 - 08:13 PM

No matter what shape the five-liter container and the three-liter containers are you can tilt them while filling them from the bottom left of the base of the container to the upper right lip of the container. By doing so, you have obtained 50% capacity. Half of the five-liter container holds 2.5 liters. Half of the three-liter container contains 1.5 liters. Once you have filled both containers in this manner, pour the liquid from the three-liter container into the five-liter container and you have the desired four liters!
  • 0




1 user(s) are reading this topic

0 members, 1 guests, 0 anonymous users