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# Pouring water IV.

30 replies to this topic

### #1 rookie1ja

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Posted 30 March 2007 - 06:09 PM

Pouring water IV. - Back to the Water and Weighing Puzzles
How can you measure 6 liters of water using only 4 and 9-liter bowls?

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### #2 Aimster73

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Posted 07 June 2007 - 07:59 PM

Hmmm. . . Couldn't you fill your 4 liter bowl all the way to the top, pour it into the 9-liter bowl, then refil the 4-liter bowl, and tilt it, so that the water line touches the opposite corner of the bottom of the bowl (think barrel), thereby spilling exactly HALF the water, then adding your now TWO liters to the 9-liter bowl, making 6 liters?

That's how I'd do it. . . right or wrong.

WHO'S WITH ME!?
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### #3 karman

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Posted 08 June 2007 - 08:08 AM

Nope, Aimster73, think what happens if your vessels are out of shape? think about a vessel that is not cylinder.
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### #4 sql_er

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Posted 19 June 2007 - 06:09 PM

What about filling up 4 liter, 6 times, and every time pouring it into the 9 liter?

That way 6 liters will spill out.

And we have thus measured out 6 liters.

The problem did not state to have the final result in one of the provided barrels, right?

Let me know who thinks what ...
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### #5 larryhl

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Posted 19 June 2007 - 09:11 PM

What about filling up 4 liter, 6 times, and every time pouring it into the 9 liter?

That way 6 liters will spill out.

And we have thus measured out 6 liters.

The problem did not state to have the final result in one of the provided barrels, right?

Let me know who thinks what ...

whenever you want to measure something, that usually means that you want to have that much. I don't think that when you're cooking and it says to measure one cup of water you spill the one cup of water on the floor...
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### #6 chunk

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Posted 23 June 2007 - 09:27 PM

You would fill up the 4 container and pour it into the 9 container. You would do this twice.
That makes 8 in the 9 container.
Then fill up the 4 container again and pour it into the 9 container.
That leaves 3 in the 4 container.
You pour out the contents of the 9 container and fill it with the 3 from the 4 contaier.
That leaves 3 in the 9 container.
Then you fill up the 4 container again an pour it into the 9 container.
That makes 7 in the 9 container.
You then fill up the four container and pour it into the 9 container.
That leaves 2 in the 4 container.
You then pour the contents of the 4 container into the emptied 9 container.
That makes 2 in the 9 container.
Then fill up the 4 container and pour it into the 9 container.

That makes 6 in the 9 container.
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### #7 townsfolk

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Posted 26 June 2007 - 09:31 PM

Fill up 9con
Poor 9con into 4con - leaving 5 in 9con.
Empty 4con
Poor 5 into 4con - leaving 1 in 9con
Empty 4Con
Poor 1 into 4con
Fill up 9con
Poor 3 from 9con into 4con (1 was already there) - leaving 6 in 9con.
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### #8 Iron_MAn_92

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Posted 26 July 2007 - 06:33 PM

I have a question, Does the 4 and 9 liter bowls have measuring marks to tell u if u have 1 liter, 2 liters, and so forth. If so, Then u could fill the 4 liter bowl with water up to the 2 liter mark. Then take the rest of the water and pour it into the 9 liter bowl. In doing this u will see that the water only goes up to the 4 liter mark. Then u add 2 liters and 4 liters to make 6 liters!

That is only if the bowls have measuring marks.

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### #9 Slick_Rick9009

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Posted 26 July 2007 - 08:31 PM

If the bowls have measuring marks then we don't need to do anything gexcept fill the 9 liter container up to where is says 6 liters. About the post that mentions not pouring the water on the floor, why would it suddenly become unusable? He never said it was going onto the floor, he could have anouther caontainer that he can pour it into. But, since he doesn't know the container's volume, he can't use it fore measuring. In cooking, can't you measure some of the water at a time if you need a lot and put that measured water into a bowl of unknown volume?
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### #10 unreality

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Posted 30 July 2007 - 04:57 PM

Fill up 9con
Poor 9con into 4con - leaving 5 in 9con.
Empty 4con
Poor 5 into 4con - leaving 1 in 9con
Empty 4Con
Poor 1 into 4con
Fill up 9con
Poor 3 from 9con into 4con (1 was already there) - leaving 6 in 9con.

thats exactly what i came up with

0/4
9/9

4/4
5/9

0/4
5/9

4/4
1/9

0/4
1/9

1/4
0/9

1/4
9/9

4/4
6/9
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