[Guest]

There are three fair 6 sided dice (A, B and C). However, they don't have the normal numbers from 1 to 6. Each die is as follows:

A - 2,2,4,4,9,9

B - 3,3,5,5,7,7

C - 1,1,6,6,8,8

The game is played between 2 people. Basically, you each pick a die and roll it once. Whoever gets the highest number wins that round. Luckily you get the choice of who gets to pick the first die. In order to win as much as possible:

1. Should you have first or second choice?

2. Which die should you choose?

[Guest]

you should take the first pick, and use dice #3.

[Guest]

(1) You chose second

(2) if they chose A, you chose B (2/3 chance win); B, you chose C; C you chose A

[hugemonkey]

choose second and make your choice based on what your opponent chooses.

A has a 4:9 chance of beating B but a 5:9 chance of beating C

B has a 4:9 chance of beating C but a 5:9 chance of beating A

C has a 4:9 chance of beating A but a 5:9 chance of beating B

So if your opponent chooses A you should choose B.

If they choose B you should choose C.

If they choose C you choose A.

This way you can always have 5:9 chance of winning.

[Guest]

Pick First and choose 1,1,6,6,8,8 and here's why:

You have a 4/6 (2/3) chance of rolling a 6 or an 8. The only numbers that can beat you are 7 and 9, which exist on separate dice.

The other player, no matter which die he or she chooses will only have a 2/6 (1/3) chance of beating you each time giving you a 2:3 win ratio.

Edited May 20, 2009 by Brodieman984

[Guest]

Wakesnow and huge monkey got it .