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#11 bonanova



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Posted 14 November 2007 - 09:02 PM

In the end, sorry to say, all they would offer for the plans was the plastic magnifying glass from a box of Cracker Jacks.

LOL - do I at least get the Cracker Jacks also? :D

I noticed crumbs on the floor so I can only assume the worst.

Are there any other rules the FCC wants to give us? Since we couldn't solve for 8 under the strict requirements, there's no way to solve for 10 with the same requirements....


Spoiler for solution

You're on an interesting track. Squares inside squares, circles inside circles, pentagons within pentagons?
They received a note from Petersen that mentioned unit graphs, whatever that is.
They were about to reach for the phone to call him, but Google might be even faster ....

That's all I can think of.
Good luck, but hurry: that fat consultant check might go to JP.
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Vidi vici veni.

#12 PDR


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Posted 14 November 2007 - 11:04 PM

I just love learning something new. Google is almost as good as duct tape and velcro - better even in some parts of the world. That Peterson guy must have been as smart as Escher since he was able to figure this out without Google. However did they do it back in 1898 without the help of Sergey and Larry to point the way?

When I agreed with Writersblock on his assessment in my previous post, we both completely missed that since each building can connect to 2 others, that means we CAN have 10 buildings given the constraints required. Since each building connects to 2 others, if we start with building #1, each of the buildings it connects to can also connect to 2 buildings, that means there are 3 sets of 3 buildings, plus the first building - or 10 buildings in all. I'd hate to spoil it and tell all how to connect the dots (so to speak) - but it can be done.

Unfortunately, I'll be unable to bid on the job as my license precludes me from working on anything resembling a hemi-dodecahedron. I'm sure I'll enjoy visiting once you do get it built though.
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#13 bonanova



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Posted 15 November 2007 - 12:01 PM

Boy, I hear ya. Those anti-hemi-dodecahedron licenses really bite.

For the interested, the walkways [ and I guess Petersen gets the stipend ] look like this.
The equal-length version is on the right.
Posted Image . . . . . Posted Image
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