(1) How many Plutonians would you need to gather before there is a 50:50 chance that two of them have the same birthday?
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#1
Posted 13 February 2009 - 10:31 PM
(1) How many Plutonians would you need to gather before there is a 50:50 chance that two of them have the same birthday?
And now, a somewhat related original puzzle...
(3) You are given a stack of cards numbered 1 to n, and their order is randomized. What is the probability that two consecutively numbered cards (lets say, a and a+1) are found consecutively (a immediately before a+1) somewhere in the stack?
Edited by EventHorizon, 13 February 2009 - 10:34 PM.
#2
Posted 13 February 2009 - 10:41 PM
#3
Posted 13 February 2009 - 10:46 PM
2)10^(10^100)/2?
3)does n stand for a variable?
#4
Posted 13 February 2009 - 11:04 PM
1) look it up. (though I did include the information needed in the spoiler)1) how many days is in their year?
2)10^(10^100)/2?
3)does n stand for a variable?
2) nope....
3) Yes, n is a variable.
#5
Posted 13 February 2009 - 11:26 PM
I'll start with extensions of Prof. Templeton's Birthday and SSN puzzles...
(1) How many Plutonians would you need to gather before there is a 50:50 chance that two of them have the same birthday?Spoiler for Pluto facts needed
And now, a somewhat related original puzzle...
(3) You are given a stack of cards numbered 1 to n, and their order is randomized. What is the probability that two consecutively numbered cards (lets say, a and a+1) are found consecutively (a immediately before a+1) somewhere in the stack?
#6
Posted 13 February 2009 - 11:59 PM
nope. For n=3, it is 1/2, but your equation gives 1/3.Spoiler for answer to #3 (I think)
#7
Posted 14 February 2009 - 12:21 AM
#8
Posted 14 February 2009 - 12:23 AM
#9
Posted 14 February 2009 - 12:26 AM
#10
Posted 14 February 2009 - 12:38 AM
Avalanche5x: You answer fails for n=3. the probability is 1/2, and you have 1/3.






