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Messed Up Math


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23 replies to this topic

#11 brhan

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Posted 24 September 2007 - 04:22 PM

NEW PROBLEM
***************

60-(3•x) = 2§

2+x = 10

what is x? and what number does § represent?



Exactly. It is much better.

Well, I think the digits on the left (and the operations applied) are in base 10, while those on the right are in base 12.

So x=10; and §=6.

60-30 = 30 which is 26 in base 12.
2+10 = 12 which 10 in base 12.
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#12 unreality

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Posted 24 September 2007 - 09:07 PM

you are wrong. "10" in any base higher than 10 has to be represented by a symbol. In base 12, 12 is 10, not 10. You should read up on your bases!

The left is base 10 of course.

But you were CLOSE with your guess of base 12 on the right
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#13 brhan

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Posted 25 September 2007 - 12:18 PM

you are wrong. "10" in any base higher than 10 has to be represented by a symbol. In base 12, 12 is 10, not 10. You should read up on your bases!

The left is base 10 of course.

But you were CLOSE with your guess of base 12 on the right



Well, that is obvious ... by 10, I mean (9+1) in base higher than 9 (and of course 12 > 9). Usually it is represented by symbol A.

BTW, I said §=26. It is just a typo. I have edited it now : §=6.
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#14 unreality

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Posted 25 September 2007 - 08:07 PM

you are wrong

But you were CLOSE with your guess of base 12 on the right


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#15 unreality

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Posted 26 September 2007 - 09:45 PM

60-(3•x) = 2§

2+x = 10



i'll tell you what § is: it is 10
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#16 brhan

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Posted 27 September 2007 - 12:36 PM


60-(3•x) = 2§

2+x = 10



i'll tell you what § is: it is 10



You got it wrong, bro .... Whatever operation u may apply and whichever base u use, you cannot get § to be 10. Now, u cannot say 2§ is to mean 2 multiplied by § b/c u used • as multiplication operator.
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#17 bonanova

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Posted 27 September 2007 - 12:43 PM

Barely noticed, the bell rings; and the opponents
sit quietly in their corners while their seconds
attend quickly to the cuts and bruises.

The bell rings for Round 4 ....
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The greatest challenge to any thinker is stating the problem in a way that will allow a solution.
- Bertrand Russell

#18 cpotting

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Posted 27 September 2007 - 04:06 PM

So x=10; and §=6.

60-30 = 30 which is 26 in base 12.
2+10 = 12 which 10 in base 12.



Seems to me that brhan's answer is valid. Why is it being rejected?
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#19 unreality

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Posted 27 September 2007 - 08:58 PM

because § is 10, and a symbol has to be used for numbers higher than 9 in bases higher than 10. He used base 12 and he said 10 outright which would be 12 not 10, a symbol (I chose § for this) would have to represent that. Anyway this is the answer (tho his answer may be right, there might be multiple answers, but not with § as ten)

60-(3•x) = 2§

2+x = 10

i'll tell you what § is: it is 10



ANSWER:

base 11.

x=9

9+2 = 11 = 10

60-(3•9) = 60-27 = 33. In base 11, 33 is 30... oops! I meant it to be 32 not 33, and 32 is 2§ in base 11. woops!

I guess the correct problem would be:

59-(3•x) = 2§

2+x = 10

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#20 brhan

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Posted 28 September 2007 - 10:33 AM

ANSWER:

base 11.

x=9

9+2 = 11 = 10

60-(3•9) = 60-27 = 33. In base 11, 33 is 30... oops! I meant it to be 32 not 33, and 32 is 2§ in base 11. woops!

I guess the correct problem would be:

59-(3•x) = 2§

2+x = 10



I assumed '§' as a place holder for a digit, b/c u didn't specify in the question that '§' is actually a symbol for unknown base.

BTW, the question has a unique solution -- and my solution is the correct one .
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