23 replies to this topic

[sunburntpixY]

I don't like this question and I can't see a clearly defined answer in this forum... AM I missing a post that says ANSWER= _____, or is the highlighting in the first post supposed to indicate that the answer is in the question or something?

[miya]

I don't like this question and I can't see a clearly defined answer in this forum... AM I missing a post that says ANSWER= _____, or is the highlighting in the first post supposed to indicate that the answer is in the question or something?

There are 2 grooves on the record, one on each side.
When a record plays, the needle continues down the same groove, otherwise you'd have to lift the needle ~833 times for each side of the record.

Edited by miya, 23 February 2008 - 09:43 PM.

[storm]

The result should be 1 per side. Because there is only one groove on each side for continuous motion of needle...otherwise..

[yomama1953]

I agree with sunburntpixy--couldn't find an answer. Either not very good or just way over my head, lol.

[ReMO08]

1 groove on each side. Looking at a record would prove it, because, as Miya said, you would need to lift the needle every time it made a revolution in order to play a full side if there were multiple grooves.
A little note, at the end of a record (middle), there is a never ending circle, so in reality there is no real end point for the needle.

[mckenzis]

One Duh

[bonanova]

One Duh

Are you sure of that answer?

[bccThis]

the phonograph spins at 33.333 revolutions in one minute, which means 33.333 grooves get traversed in 1 minute.

if there are 50 minutes of play on the record, this translates to their being 50 * 33.3333 = 1666.66665 grooves on the record.

for this to be correct, the record should also play 1 minute worth of sound at 33 1/3 revolutions.

I am not sure what the 0.6666 groove represents though.

[Lost in space]

the phonograph spins at 33.333 revolutions in one minute, which means 33.333 grooves get traversed in 1 minute.

if there are 50 minutes of play on the record, this translates to their being 50 * 33.3333 = 1666.66665 grooves on the record.

for this to be correct, the record should also play 1 minute worth of sound at 33 1/3 revolutions.

I am not sure what the 0.6666 groove represents though.

He he!! - great math - how does the needle go from one grove to the other ?? does it have the same on the other side ?? = O+M+G !!!

[bccThis]

He he!! - great math - how does the needle go from one grove to the other ?? does it have the same on the other side ?? = O+M+G !!!

there was no mention of the record having grooves on both sides. but if that is case, and if we are to count the grooves as one on each side since the groove is connected from the inside all the way to the outside (as opposed to counting the grooves in a straight line) then there are two grooves on the record.