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# Christmas Tree

44 replies to this topic

### #11 BoilingOil

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Posted 26 September 2007 - 12:37 AM

Christmas Tree - Back to the Logic Puzzles
There were 4 angels on a Christmas tree (besides other frou-frou). Two had a blue aureole and two yellow, however none of them can see behind his head. Angel A is on the highest place and he can see angels B and C, which hang below him. Below hangs angel B, who can see only angel C under him. Angel C can't see anybody, because angel D hangs under a twig (nobody can see him and he can not see anyone either).
Which one of them will be the first to guess (Edit: speak his guess out load, deduce and say) what his own aureole is?

To me it looks like this is an edited version of the Headbands riddle: A sees B and C, B sees only C, C sees nothing, and D can be left out of the equation.
So C is like white man 1, B like man 2, and A like man 3, however there are now two white (yellow) and two red (blue) bands (aureoles).

Since the colors of the aureoles are equally devided, there's no clue as to what color will be guessed, but one thing is sure:

Only Angel A has an easy shot to guess something, and that only if he sees two equal colors beneath him.
But if we assume they are all equally smart, then B must realize this and, assuming A keeps silent, be able to guess his color is different from C's

Apart from that, we know nothing...

That is my logic, now I will go look at the solution

Thank you for these excellent riddles! I'm having a hard time with most of them, and I'm considered not to be dumb

BoilingOil
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### #12 bob

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Posted 07 October 2007 - 05:30 PM

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### #13 bob

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Posted 07 October 2007 - 05:32 PM

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### #14 credels

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Posted 12 October 2007 - 06:04 PM

What shade of yellow are the aureoles? A light yellow aureole could easily be mistaken for blonde hair confused the angel. Or the blue might have been mistaken for a noble pine needle which has a bit more blue than green in it.
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### #15 ali500

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Posted 22 October 2007 - 05:04 PM

What if all the angels was very smart because she was made by Dumbldore (don't ask why Dumbldore would make an angel for a christmas tree) so they atomaticlly know what color they were wearing and they all spoke at the same time?
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### #16 Gopher of Pern

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Posted 06 November 2007 - 11:44 AM

I heard this exact same riddle, just worded differently. It clears up some issues u guys have:

4 men were about to be executed by firing squad. However, the prison guard decided to play a game. He placed 4 hats, 2 white and two black, on the men so that 1 and 3 had white, and 2 and 4 had black. He then placed them all in a line, all facing one direction. There was a wall between 3 and 4. So 1 could see 2 and 3, 2 could see 3, 3 could see the wall, and 4 could see nothing. He told the men that there are 2 white and 2 black hats, and if one of you can tell me which hat you have on, you all go free. Tell me wrong, and you will be shot. None of the men are stupid enough to guess which hat they have. Which man can exactly tell which hat they have on?

Same problem, worded slightly better
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### #17 souperman123

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Posted 10 November 2007 - 05:56 PM

why dont they just ask or look in a mirror? is it all that hard? seriously?
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### #18 elegir

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Posted 12 November 2007 - 04:07 PM

The prisoners in hats isn't always clear-cut either. If the 4 prisoners are required to shout out their colours, the following possibilities occur:

If 2 and 3 have the same colour hats, then 1 can call the opposite colour as his own. 2 and 3 can then call the opposite colour from 1, and 4 can call the same colour as 1. All prisoners escape.

If the prison guard was smart enough to recognise this logic and put different colour hats on 2 and 3, then 1 would be silent and 2 would call the opposite of 3's colour, allowing 3 to identify his own hat colour.

So in both situations, 2 and 3 escape. Now if 1 or 4 takes a risk and calls a random colour, the other prisoner can tell if that was wrong (by the sound of a gunshot followed by dying sounds) or correct -- again allowing the other prisoner to correctly identify his own colour.

In sum, three of the four prisoners should escape, and the 4th one might escape. You can't identify in advance if someone will die or who that someone will be.
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### #19 Sinsemilla

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Posted 20 November 2007 - 11:58 PM

I believe that "Which one of them will be the first to guess?" is the correct wording for this question. At first I did come up with the answer that was in the solution, but then I thought about it some more. The question specifically states that the angels cannot see every other angel; also, they also are not able to see behind their own head. Therefore, they cannot determine how many of each color there are. Without stating that they have access to this knowledge, their only possible responses would be uneducated guesses.

I checked the Masters of Logic questions, and in each of them it specifically says that they are aware of the possible choices. Sorry, but this puzzle does not compute.
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### #20 rookie1ja

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Posted 21 November 2007 - 12:28 AM

I believe that "Which one of them will be the first to guess?" is the correct wording for this question. At first I did come up with the answer that was in the solution, but then I thought about it some more. The question specifically states that the angels cannot see every other angel; also, they also are not able to see behind their own head. Therefore, they cannot determine how many of each color there are. Without stating that they have access to this knowledge, their only possible responses would be uneducated guesses.

I checked the Masters of Logic questions, and in each of them it specifically says that they are aware of the possible choices. Sorry, but this puzzle does not compute.

good point ... I have edited the puzzle ... check the wording for other improvements
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