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Posted 13 June 2007 - 01:36 PM
Posted 14 June 2007 - 02:14 PM
Veracity, you're a little off. The answer to the brain teaser is that the train to New York is closer to New York when it meets the train from Boston. Why? Because things in this world have mass, they aren't points. If everything was points, then yeah, they'd be the same distance from New York when they meet. But think about it, trains are LONG (usually). So that means while the engines of both trains have met, you still have all those cars behind the engine to account for. So obviously, the train coming from New York is still closer to New York.
YEP!! Makes sense...LOL
Posted 19 June 2007 - 06:42 AM
Posted 19 June 2007 - 12:05 PM
You know...you really don't have to be so rude about it. I don't know any of you people here. But I think it's something to try to figure out the answers to these logic questions without someone name calling. Why can't you explain things without being so rude?
I'm not really sure who you are talking about, but if it was me, and I upset you, then I am VERY SORRY!!!.....
Hold on, I think I,,,,, (
Ahhhh, There it is......
THE ONLY PERSON BEING RUDE, IS YOU!!! WE ARE JOKING AROUND WITH EACHOTHER WITH ABSOLUTELY NO EMOTION BEHIND ANYTHING WE ARE SAYING. YOU ARE RIGHT, YOU "DO NOT" KNOW ANY OF US YET ARE JUDGING OUR ACTIONS AS IF YOU DO.
We come here everyday and have fun with the Logic puzzles, however it would be quite a boring place without a little Sense of Humor. This is a prime example... You can either read my response and get upset, or TAKE IT WITH A GRAIN OF SALT and tell me TO ATTEND A FEW ANGER MANAGMENT CLASSES...lol..(( I would much rather the Sarcastic "Anger Management comeback myself _))
Are you one of us?
Posted 20 June 2007 - 02:51 PM
Posted 22 June 2007 - 01:24 PM
Posted 03 July 2007 - 08:19 PM
Posted 25 July 2007 - 03:50 AM
the distance from boston and new york isn't important here. Consider that the distance is "x" and consider that both trains are points (because of physics' theory). Using the linear uniform movement equation, you get the following expression:
t1 = x / v (train that leaves new york)
t2 = x / 2v (train that leaves boston)
t1 = time to smack into eachother
t2 = time to smack into eachother
x = distance from new york to boston
As you can see, the faster is the speed the lesser wil be the time to encounter a point that the two trains will smack into eachother. So, if you take a half of time to get the other side of city, probably the two trains will be in the same distance from new york when they encounter eachother.
Posted 18 August 2007 - 02:08 AM
But yeah, I think I see the point. It's a trick question.
Which train will be closer to New York when they encounter?
When the trains encounter each other, they are technically both the same distance away from Pt. A (because they are on the same point on the line between Pt. A and Pt. B.).
[Boston]----------------------------------[wherever the trains have met eachother]---------[New York]
So no matter how fast one train is going versus the other, the distance between the encounter point and New York are the same for both trains (unless you're counting the fact that the train leaving New York has a caboose that's closer to New York than the train leaving Boston).
Does that settle the dispute?
Posted 18 August 2007 - 05:55 PM
Otherwise, there are many answers for this question.
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