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Aeroplane
#21
Posted 16 November 2007 - 11:01 PM
rookie1ja (site admin)
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#22
Posted 29 November 2007 - 04:04 PM
#23
Posted 10 December 2007 - 01:35 AM
A1 = 1st Plane
A2 = 2nd Plane
A3 = 3rd Plane
They fly counter-clockwise. (NP-1-2-3-SP-4-5-6-NP)
North Pole
(Point 1) (Point 4)
(Point 2) (Point 5)
(Point 3) (Point 6)
South Pole
A1 starts
A2 starts
A1 gets to 75% fuel (Point 1)
A2 gets to 75% fuel (Point 1)
A1 gives 25% of fuel to A1
A1 has 100% fuel
A2 returns and refuels
A1 get to 75% fuel (Point 2)
A2 flies to (Point 2)
A2 gives 25% to A1
A1 has 100% fuel
A3 flies to (Point 1)
A2 flies to (Point 1)
A3 gives 25% fuel to A2
A2 has 25 % fuel
A3 returns and refuels
A2 returns and refuels
A1 flies to the South Pole
A2 flies to (Point 5)
A1 flies to (Point 5)
A2 gives 25% fuel to A1
A1 has 25% fuel
A2 has 25% fuel
A1 flies to (Point 6)
A2 flies to (Point 6)
A3 flies to (Point 6)
A3 gives 25% fuel to A1
A3 gives 25% fuel to A2
A1 has 25 % fuel
A2 has 25 % fuel
A3 has 25 % fuel
A1 flies to the North Pole
A2 flies to the North Pole
A3 flies to the North Pole
*CONGRATS* If you have got to this point you have nothing more to read.
This shows it can be done!
Like the solution?
#24
Posted 18 December 2007 - 06:58 AM
#25
Posted 25 January 2008 - 12:54 AM
#26
Posted 28 February 2008 - 05:16 PM
#27
Posted 19 March 2008 - 06:16 PM
Nice job PAUL in explaining the solution with a detailed diagram.
#28
Posted 20 March 2008 - 02:54 AM
#29
Posted 05 April 2008 - 10:46 AM
good explanation. i 2 solved the puzzle this way.I believe this is a solution (that doesn't require planes to hover):
Let the fraction of fuel-tank-filled for planes A, B, and C (respectively) be represented as:
[1, 1, 1]
<!-- ia0 -->airplane_puzzle.gif<!-- ia0 -->[/attachment:6a5ea]
1. All 3 planes go 1/4 the way toward the south pole. [3/4, 3/4, 3/4]
2. At that point plane C gives 1/4 tank to EACH of the other planes, leaving them full, and plane C with 1/4 tank to return to the north pole. [1, 1, 1/4]
3. At the equator, plane B gives plane A (the "full-circle plane") 1/4 tank, thus filling plane A; plane B has 1/2 tank left to return to the north pole. (Plane C arrives at airport) [1, 1/2, 1]
(Plane A now has enough fuel to pass the south pole and reach the equator on the other side.)
4. When plane B arrives at the airport, both B and C must instantly refuel and leave going the other direction. [1/2, 1, 1]
5. At 1/4 the way from the north pole, plane C gives plane B 1/4 tank, filling it up, while leaving itself with 1/2 tank to get back with (plenty). [1/4, 1, 1/2]
6. Plane B meets plane A at the equator as plane A is running out of fuel. Plane B, which has 3/4 tank left, gives half its fuel to plane A, leaving 3/8 tank in each plane. Plane C reaches the airport at this same time. [3/8, 3/8, 1]
7. Plane C instantly refuels and goes back to meet planes A and B at 1/4 the way from the north pole, with plenty of fuel for all three to return safely. [1/8, 1/8, 3/4] --> [1/3, 1/3, 1/3]
It sounds a bit messy, and I assume things happen instantly, but it works, doesn't it??
#30
Posted 11 April 2008 - 04:54 AM
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