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# Impossible math 2

14 replies to this topic

### #11 comperr

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Posted 16 July 2007 - 03:08 AM

right - I didn't have to because I limited my explication the math concept I used. However it is saying the same thing in the end: there are two possible values and therefore we need limit the scope of certain rules.
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### #12 infomaniac.nick

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Posted 17 July 2007 - 04:24 PM

Comperr,

Sorry mate but you are wrong on this one.
You can't say that the sqrt of -1 is -1 if you do not include the imanginary i in the formula... You just can't!

However, I have seen this:

0 = 0+0+0+0...
= (1-1)+(1-1)+(1-1)+(1-1)+... [to infinity]
= 1+(-1+1)+(-1+1)+(-1+1)+... [there will always be another +/- to pair with]
= 1+0+0+0+0+0...
= 1

You can therefore get m=0=n, where n and m are any real or imaginary number.
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### #13 unreality

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Posted 17 July 2007 - 10:48 PM

nice... of course the flaw is the "infinity" part, which corresponds to the "light switch supertask paradox" centered around aleph-null and that scientists dont know if an event has occured even or odd times when it reaches aleph-null (infinity)... well i cant explain it very well but its one of Martin Gardner's books

nick, that was a good use of the aleph-null paradox!
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### #14 comperr

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Posted 22 July 2007 - 02:45 PM

I actually posted this elsewhere. And I am not wrong by the way with the math. The idea behind most zero based math are the rules that change things for zero. Same thing with negatives. The false math uses the global rules ignoring the exceptions. Your problem with my math is the fact that I ignored an exception. I recommend you read a few books on false math.
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### #15 mathemagister

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Posted 23 July 2007 - 09:43 AM

Comperr,

Sorry mate but you are wrong on this one.
You can't say that the sqrt of -1 is -1 if you do not include the imanginary i in the formula... You just can't!

However, I have seen this:

0 = 0+0+0+0...
= (1-1)+(1-1)+(1-1)+(1-1)+... [to infinity]
= 1+(-1+1)+(-1+1)+(-1+1)+... [there will always be another +/- to pair with]
= 1+0+0+0+0+0...
= 1

You can therefore get m=0=n, where n and m are any real or imaginary number.

Cool! If anyone didn't know about aleph-null, this would sure baffle 'em!
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