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Posted 10 June 2008 - 07:53 PM
The Bellboy pockets two dollars and gives each person three.
Person 1: 1
Person 2: 1
Person 3: 1
Add all that up. 25+2+1+1+1= 30
They try to confuse you my making you think each person paid nine, so the manager has 27, and the three people have nothing. TRICKY!
Posted 17 June 2008 - 01:48 AM
Posted 29 July 2008 - 07:09 AM
That is the only way this problem has been explained, that actually made sense to me.
This has always been one of my favorite logic puzzle due to its nature of trying to misinform you and make you run with that information. The first time I heard it I spent hours trying to figure out what was up with the 29 dollars before realizing it had nothing to do with the problem, each person paid 9 dollars because the money the bell boy took is factored into their cost.
Posted 30 July 2008 - 11:51 AM
Posted 11 October 2008 - 04:01 PM
So, they paid $9 each so $27. $25 of this the manager has and $2 the bellboy has. The remaing $3 is the money that they got returned to them and is now back in their possesion.
Posted 18 October 2008 - 01:58 AM
original transaction: $10 + $10 + $10 = $30 - $5 ($3 returned to the customers, $2 pocketed by the bellboy) = $25
post transaction": $9 + $9 + $9 (now that the $3 have been returned to the customers) = $27 -$2 (now in the bellboy's pocket) = $25
the phrasing of the riddle leads you to believe that the equation requires re-adding the $2 to balance the equation by also leading you to believe that the sum you are looking for is $30, when in fact it is $25, the real cost of the room!
Posted 01 November 2008 - 06:04 AM
$30-$5 = $25 = ($25/3 people)*($5-$2)
= ($25/3 people)*($3)
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