Guest Posted April 9, 2008 Report Share Posted April 9, 2008 Solve for x without a calculator. 2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/4895-5884*102504=(square root of x)*698/56x*589x*42x+69/(square root of -90) Remember: No calculator. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 Solve for x without a calculator. 2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/4895-5884*102504=(square root of x)*698/56x*589x*42x+69/(square root of -90) Remember: No calculator. I'm still trying to decide whether you're looking for me it's not possible because you're doing square roots of negative numbers or if I should just go ahead and ask whether that's a 698/(56x) or (698/56)x and use complex numbers if needed. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 I'm still trying to decide whether you're looking for me it's not possible because you're doing square roots of negative numbers or if I should just go ahead and ask whether that's a 698/(56x) or (698/56)x and use complex numbers if needed. Complex numbers are needed. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 Not possible for two reasons I see. 1. Your doing squareroots of negatives which are imaginary numbers. 2. You can't have radicals in the denominator of a fraction. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 Not possible for two reasons I see. 1. Your doing squareroots of negatives which are imaginary numbers. 2. You can't have radicals in the denominator of a fraction. Just to clarify, the slashes are divide. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 Just to clarify, the slashes are divide. That's why I was saying that. Quote Link to comment Share on other sites More sharing options...
0 EventHorizon Posted April 9, 2008 Report Share Posted April 9, 2008 Solve for x without a calculator. 2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/4895-5884*102504=(square root of x)*698/56x*589x*42x+69/(square root of -90) Remember: No calculator. Just as a matter of clarification.....please fully parenthesize the equation (at least with regard to division)... 2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/(4895-5884*102504)=(square root of x)*698/(56x*589x*42x+69/(square root of -90)) ? or 2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+(36698/4895)-5884*102504=(square root of x)*(698/56x)*589x*42x+69/(square root of -90) ? And as a response to DemonWolf44, "Not possible for two reasons I see." 1. Your doing squareroots of negatives which are imaginary numbers. yes...the answer may or may not be a complex number.....that doesn't mean it isn't possible. 2. You can't have radicals in the denominator of a fraction. Sure you can, and you can move them if needed. (eg, 1/sqrt(2) = sqrt(2)/(sqrt(2)*sqrt(2)) = sqrt(2)/2 ) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 To tell the truth, i just threw down a bunch af random numbers to see if it can be solved. I belive it can be solved if you look at it carefully. Also, this equation does not consist of fractions. / is also another symbol for divide. I will be more careful to make future puzzles/problems clearer and easier to understand. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 9, 2008 Report Share Posted April 9, 2008 To tell the truth, i just threw down a bunch af random numbers to see if it can be solved. I belive it can be solved if you look at it carefully. Also, this equation does not consist of fractions. / is also another symbol for divide. I will be more careful to make future puzzles/problems clearer and easier to understand. Haha. Did I read that correctly?? The problem that YOU put down MIGHT have an answer but YOU'RE NOT SURE?! Hahahaha. Wow...I'd post a picture of a short bus but I have to go play some tennis. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 10, 2008 Report Share Posted April 10, 2008 2. You can't have radicals in the denominator of a fraction. Sure you can, and you can move them if needed. (eg, 1/sqrt(2) = sqrt(2)/(sqrt(2)*sqrt(2)) = sqrt(2)/2 ) Or another example... What about 1/sqrt(4)? Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 10, 2008 Report Share Posted April 10, 2008 Or another example... What about 1/sqrt(4)? Isn't the radical in the denominator thing just one of those formalities?? I can't remember terminology, but if you do encounter a 1/sqrt(4), then just multiply it by sqrt(4)/sqrt(4) (conjugate might be term??). That way it looks prettier to those who don't like radicals in denominator. 1/sqrt(4) = sqrt(4)/2. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 10, 2008 Report Share Posted April 10, 2008 Isn't the radical in the denominator thing just one of those formalities?? I can't remember terminology, but if you do encounter a 1/sqrt(4), then just multiply it by sqrt(4)/sqrt(4) (conjugate might be term??). That way it looks prettier to those who don't like radicals in denominator. 1/sqrt(4) = sqrt(4)/2. Except it would be 1/sqrt(4) = sqrt(4)/4 Since sqrt(4) = 2 thus, 1/2 = 2/2 (in your showing) Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 10, 2008 Report Share Posted April 10, 2008 To tell the truth, i just threw down a bunch af random numbers to see if it can be solved. I belive it can be solved if you look at it carefully. Also, this equation does not consist of fractions. / is also another symbol for divide. I will be more careful to make future puzzles/problems clearer and easier to understand. When did fractions become different than dividing? Quote Link to comment Share on other sites More sharing options...
0 itachi-san Posted April 10, 2008 Report Share Posted April 10, 2008 When did fractions become different than dividing? When this got posted Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 11, 2008 Report Share Posted April 11, 2008 Except it would be 1/sqrt(4) = sqrt(4)/4 Since sqrt(4) = 2 thus, 1/2 = 2/2 (in your showing) Yeah so I screwed that one up when I typed it because my multitasking ability SUCKS. 1/sqrt 4 = 1/2 multiply 1/sqrt (4) times sqrt (4)/sqrt (4) = sqrt (4)/4. Therefore, 1/2 = 1/2 Obviously the 2 in the denominator was supposed to be a 4. I guess everyone else realized that, though, but glad you probably feel better for doing such an "advanced proof." Also, I'm taking up collections to hire "giterdone" a tutor. My 3rd grade cousin made an A in math last semester, so I was thinking of hiring him. Quote Link to comment Share on other sites More sharing options...
Question
Guest
Solve for x without a calculator.
2x^(square root of -78)*33x+-(587/369)x*(square root of -982)+36698/4895-5884*102504=(square root of x)*698/56x*589x*42x+69/(square root of -90)
Remember: No calculator.
Link to comment
Share on other sites
14 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.