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Hotel


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63 replies to this topic

#51 monk3ybutt3r

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Posted 14 August 2008 - 05:59 PM

The second guest is left in the lobby therefore has a room to himself.
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#52 khildress

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Posted 10 September 2008 - 05:53 PM

Of the 13 people who want their own rooms, 2 are a couple. And the couple gets their own room.
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#53 GabrownzFan

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Posted 24 September 2008 - 02:06 AM

Here is how it works

1 - Guest 1 & 2 (for the time being)
2 - Guest 3
3 - Guest 4
4 - Guest 5
5 - Guest 6
6 - Guest 7
7 - Guest 8
8 - Guest 9
9 - Guest 10
10 - Guest 11
11 - Guest 12
12 - Guest 2

Oh - thought it worked - guess not - sorry - not sure if this is right or not?

Edited by GabrownzFan, 24 September 2008 - 02:10 AM.

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#54 HeatherCalifornia

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Posted 02 October 2008 - 11:02 PM

Rookie you always post these "not possible" puzzles and I hate them. Give me a puzzle you can solve :P
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#55 zoris

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Posted 04 October 2008 - 09:38 PM

Hotel - Back to the Logic Puzzles
13 men came into a hotel with 12 rooms and everybody wanted his own room. The bellboy solved this problem.
He asked the thirteenth guest to wait a moment with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, ... and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to empty room number 12.
How can everybody have his own room?


Spoiler for Solution


This quiz is similar to this one:
"Horses": if you had nine boxes and you had to fit ten horses in them how would you do it? posted by xXspygirlXx
http://brainden.com/...wto... box&st=0
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#56 peace*out

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Posted 04 October 2008 - 10:41 PM

What if they didn't come in at the same time??

guest 1 to room 1
guest 2 to room 2
guest 3 to room 3
ect..........

when you get to the thirteenth guest, guest one has checked out, so he get's a room!!


or..........


Who ever said 2 of them wern't a couple??
2 twins, or a double!!
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#57 tinman80222

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Posted 27 October 2008 - 05:36 AM

Hotel - Back to the Logic Puzzles
13 men came into a hotel with 12 rooms and everybody wanted his own room. The bellboy solved this problem.
He asked the thirteenth guest to wait a moment with the first guest in room number 1. So in the first room there were two people. The bellboy took the third guest to room number 2, the fourth to number 3, ... and the twelfth guest to room number 11. Then he returned to room number 1 and took the thirteenth guest to empty room number 12.
How can everybody have his own room?


Spoiler for Solution


:rolleyes:

This is possible when you assume the rooms are numbered 1-12. A lot of hotels do not have a room #13, since it is considered 'unlucky'. therefore they skip a number of use a number twice even. This is the case here. The first and second guest were together so that no one would figure out that they actually had the thirteenth room.
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#58 RyanJ

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Posted 27 October 2008 - 07:15 PM

:rolleyes:

This is possible when you assume the rooms are numbered 1-12. A lot of hotels do not have a room #13, since it is considered 'unlucky'. therefore they skip a number of use a number twice even. This is the case here. The first and second guest were together so that no one would figure out that they actually had the thirteenth room.



I understand what you are saying, but you are changing the story. It states that 12 rooms are available; not that the rooms 1-12 are available. If the ladder were the riddle I would have to concede your point; which is a valid observation. Unfortunately, it does not apply in this scenario.
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#59 Pawtamus

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Posted 12 November 2008 - 04:21 AM

it says "his". maybe one of the people is a "her" who can stay with with one of the other males! <_<
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#60 logicalist

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Posted 18 November 2008 - 02:30 AM

they write "room" on thirteen different pieces of paper and each keep one.
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