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Matchstick Equations


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#21 Buddyru

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Posted 17 August 2008 - 08:00 AM

VII = I

 √1 = 1 (square root of 1 = 1)

Or you could get "complex" ;)

V-II = I

√-1 = i (square root of -1 = i)
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#22 Wlado

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Posted 20 August 2008 - 09:24 PM

What about the first one?
Instead of: XI-V=IV ; IX-V=IV
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