Guest Posted April 5, 2008 Report Share Posted April 5, 2008 You're given 9 empty boxes and the digits from 1 to 9. Each digit may only be used once and only one digit can be used in one box. Find some permutation of the digits such that Have fun. Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 5, 2008 Report Share Posted April 5, 2008 YUCK!!! this is not funny Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 5, 2008 Report Share Posted April 5, 2008 i am getting an approximate value- 99.66 7/2 * 6 + 5*4*1/3 + 9*8 Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 5, 2008 Report Share Posted April 5, 2008 (9/1)x7 + (2 x 5 x 3)/6 + (4x8) = 100 even First post, took about 10 minutes. Very fun! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 5, 2008 Report Share Posted April 5, 2008 First post, took about 10 minutes. Very fun!(9/1)x7 + (2 x 5 x 3)/6 + (4x8) = 100 even Herzlichen Glückwunsch!!! Sehr gut!! Quote Link to comment Share on other sites More sharing options...
0 Guest Posted April 5, 2008 Report Share Posted April 5, 2008 First post, took about 10 minutes. Very fun!(9/1)x7 + (2 x 5 x 3)/6 + (4x8) = 100 even Well done, Sauer! There is at least one more possibility, so keep on trying, people! I changed the pic a little, hope it helps. Quote Link to comment Share on other sites More sharing options...
Question
Guest
You're given 9 empty boxes and the digits from 1 to 9. Each digit may only be used once and only one digit can be used in one box. Find some permutation of the digits such that
Have fun.
Link to comment
Share on other sites
5 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.