Posted 03 February 2010 - 05:09 AM
Here's some of my reasoning in solving this puzzle. Numbers "0 thru 9" are all used.
It is obvious that S="5" for "S" to be in the same column and part of the sum,
The letter "O" must ="9" in order to have a "1" carried over to the "K" so that T=K+1.
This is done by adding the "1" to the "9", carried over from "15" (5+5+5) and the "1" is
carried over again to the "K" from "10" (1+9). "A" must ="0" from the process.
Now we can go back and solve for the letters "U,N,I". We have now used numbers "0,5,9"
If we substitute "2" for "U", then "N=7" and If "N=7", then "E=1". "U" cannot ="1" because "N" would then ="9"
We have numbers "3,4,6,8" left. Since T=K+1, only "3 & 4" will work, leaving numbers "6 and 8" for letters "I and G'.
The rest went really fast.