Best Answer Yoruichi-san, 29 June 2014 - 09:07 PM

The height of point P, i.e. the distance between P and D.

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Started by BMAD, Jun 25 2014 11:22 PM

Best Answer Yoruichi-san, 29 June 2014 - 09:07 PM

The height of point P, i.e. the distance between P and D.

Spoiler for Now that I have more time...

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13 replies to this topic

Posted 25 June 2014 - 11:22 PM

A point P needs to be located somewhere on the line AD so that the total length L of cables linking P to the points A, B, and C is minimized. What is the minimum value of L?

My image won't upload so you can see it here:

https://docs.google....sp=docslist_api

My image won't upload so you can see it here:

https://docs.google....sp=docslist_api

Posted 26 June 2014 - 12:12 AM

For those who can't access this image:

There is a triangle BPC where on one line segment BC there is a point D such that BD=2 and DC=3. Extending through P is a line segment going from some point A to D which is a distance of 5 and perpendicular to BC. Find the minimum total distance of all the "cables" by placing p in an optimal place.

There is a triangle BPC where on one line segment BC there is a point D such that BD=2 and DC=3. Extending through P is a line segment going from some point A to D which is a distance of 5 and perpendicular to BC. Find the minimum total distance of all the "cables" by placing p in an optimal place.

**Edited by BMAD, 26 June 2014 - 12:13 AM.**

Posted 28 June 2014 - 05:19 PM

hint: pythagoras is a straightforward approach

Posted 28 June 2014 - 07:40 PM

Would anyone who's able to access the image be able to attach it as a figure?

From the description, I'm not sure what the cables are whose distance needs to be minimized.

From the description, I'm not sure what the cables are whose distance needs to be minimized.

Posted 28 June 2014 - 10:42 PM

I got the same figure.

But, with plasmid, I don't know where the cables are.

Assumption (from post 1): We are to minimize PA + PB + PC.

- Bertrand Russell

Posted 29 June 2014 - 12:12 AM

Spoiler for I get...

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Posted 29 June 2014 - 03:12 AM

Thanks, kukupai.

I haven't fully worked out the equations, but I don't think that's it.

Spoiler for counterexample

Posted 29 June 2014 - 04:07 AM

Spoiler for Corrected using mathematica

<3 BBC's Sherlock, the series and the man. "Smart

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Posted 29 June 2014 - 07:02 AM

Agree with Y-san's answer.

Spoiler for Using iterative method

- Bertrand Russell

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