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Guest Message by DevFuse
Probability: equal sequences
5 replies to this topic
Posted 14 April 2014 - 02:58 AM
Try out (or imagine) the following simple game with a friend:
You each toss a fair coin as many times as necessary to get a required sequence.
Your required sequence is H T H
Your friend's required sequence is H T T.
Do this several times and each time write down the number of tosses you needed
The winner is the player whose average number of tosses is the lowest. For example:
You toss: H T T H T H
Friend tosses: H T H H H T H H T T
Your 'score' is 6 and your friend's is 10
You toss: T T H T T H H T H
Friend tosses: T T H H T H T T
Your 'score' is 9 and your friend's is 8
You toss: T T H H T H
Friend tosses: H H T H T T
You both 'score' 6.
At this point your average is 7 and your friend's average is 8.
The conundrum: Assuming you played the game many times, which of the following outcomes would you expect?
A) You win (i.e. your average is lower than your friend's).
B) Your friend wins (your average is higher than your friend's).
C) You tie (your average is about the same)
Posted 14 April 2014 - 08:31 PM Best Answer
Spoiler for I would say
Edited by Rob_G, 14 April 2014 - 08:31 PM.
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