Best Answer harey, 10 May 2014 - 08:27 PM

Welcome to BrainDen.com - Brain Teasers Forum. Like most online communities you must register to post in our community, but don't worry this is a simple free process. To be a part of BrainDen Forums you may create a new account or sign in if you already have an account. As a member you could start new topics, reply to others, subscribe to topics/forums to get automatic updates, get your own profile and make new friends. Of course, you can also enjoy our collection of amazing optical illusions and cool math games. If you like our site, you may support us by simply clicking Google "+1" or Facebook "Like" buttons at the top. If you have a website, we would appreciate a little link to BrainDen. Thanks and enjoy the Den :-) |

Guest Message by DevFuse

Started by BMAD, Mar 14 2014 05:42 PM

Best Answer harey, 10 May 2014 - 08:27 PM

Spoiler for Surprisingly, the answer does not depend so much on the total number of computers, but mainly on the number of suspicious computers. And even more surprisingly, there is no "worst case" neither "best case". An even more general solution working for k suspicious computer and at least (k+1) good computers:

Go to the full post
12 replies to this topic

Posted 20 March 2014 - 11:08 PM

Spoiler for spoiler

**Edited by bonanova, 21 March 2014 - 06:24 AM.**

spoiler

Posted 10 May 2014 - 08:27 PM Best Answer

Spoiler for Surprisingly, the answer does not depend so much on the total number of computers, but mainly on the number of suspicious computers. And even more surprisingly, there is no "worst case" neither "best case". An even more general solution working for k suspicious computer and at least (k+1) good computers:

Posted 24 May 2014 - 09:44 AM

this answer assumes that we know the number of bad computers, but we don't. what is the actual answer?

0 members, 0 guests, 0 anonymous users