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Guest Message by DevFuse

# Making 271

7 replies to this topic

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Posted 25 February 2014 - 05:41 PM

Using positive integers only, how many ways can can the sum of 271 be found?

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### #2 Perhaps check it again

Perhaps check it again

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Posted 25 February 2014 - 07:02 PM

Is this with regards or without regards to orderings of the summands?

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### #3 bonanova

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Posted 25 February 2014 - 09:13 PM

Is this with regards or without regards to orderings of the summands?

I would guess "ways" means combinations.

The permutations of 271 1's are not that interesting.

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Vidi vici veni.

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Posted 26 February 2014 - 12:35 AM

Yes. I mean combinations.
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### #5 superprismatic

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Posted 26 February 2014 - 02:16 AM

I'll bet that the answer is divisible by 7.

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### #6 Perhaps check it again

Perhaps check it again

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Posted 26 February 2014 - 06:52 AM

bonanova posted:

-------------------------------------------------------------------------------

I would guess "ways" means combinations.

The permutations of 271 1's are not that interesting.

-------------------------------------------------------------------------------

I must be a genius when it comes to making arguments, because I would never have typed

that second sentence highlighted above.  It is irrelevant.

But your second sentence, bonanova, is irrelevant.  It's on purpose that I try really hard

not to resort to sarcasm with another math forum user when I don't understand why they

stated something that I otherwise would not have stated myself.  And now it should be an

insult for me to point out that the permutations of 271 1's doesn't exclude the possibility of

interesting permutations of other than the sole use of 1's to sum to 271.

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### #7 bonanova

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Posted 26 February 2014 - 11:25 AM

Perhaps, sorry for any misunderstanding.

No sarcasm was intended, nor would I want anyone to express sarcasm in this forum.

Your question was proper, and my guess as to its answer was based on the fact

that the total would be swamped by counting trivial permutations, while the count

of combinations seems an interesting problem.

I don't yet have the solution. SP has posted a clue. I'll leave the solution to you.

Good Luck.

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Vidi vici veni.

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Posted 26 February 2014 - 04:57 PM

Be nice friends.  This is a math forum not a drama forum.  I saw and took no offense in either post.

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