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Betting Paradox


Best Answer Rainman, 13 November 2013 - 12:25 AM

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#1 BMAD

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Posted 12 November 2013 - 03:37 AM

Here is a challenge for you guys:

 

Design three betting games where when played individually or in pairs are losing games but when all three are played in some alternating pattern the combined effect provides a positive result to the player.

 

**Make sure that the pair games are always result in a lost for player regardless of the way the player plays**


Edited by BMAD, 12 November 2013 - 03:38 AM.

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#2 Rainman

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Posted 13 November 2013 - 12:25 AM   Best Answer

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#3 BMAD

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Posted 20 November 2013 - 11:04 PM

I am not sure If I understand your games.  Besides each game is supposed to be a losing game for the player if the player played it exclusively.


Edited by BMAD, 20 November 2013 - 11:05 PM.

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#4 phil1882

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Posted 21 November 2013 - 07:47 PM

so the games are as follows. if the number of games played is evenly divisable by 3, pay 3, roll a dice and take money equal to roll.

else pay 599 dollars, roll 100 dice and get money equal to roll. the other two games are the same, except for the slight differance of number of games being +1 evenly divisalbe by 3, and +2 evenly divisible by 3.

this system meets the nessicary criteria. that is any single game or any two games picked are definately losing, since at least 1/3 games will be severely losing. but if you can play all 3 in any order. you can simply play the first game then second game then third game and back to first and have a winning strat.


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#5 BMAD

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Posted 22 November 2013 - 12:21 AM

Thank you for clarifying. Phil.
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