TimeSpaceLightForce Posted October 31, 2013 Report Share Posted October 31, 2013 If i toss 100 dollar bills from the top of a building ,what is the chance that more of them landing up side down on the ground? Quote Link to comment Share on other sites More sharing options...
0 superprismatic Posted October 31, 2013 Report Share Posted October 31, 2013 about 0.46 Quote Link to comment Share on other sites More sharing options...
0 Joyandwarmfuzzies Posted October 31, 2013 Report Share Posted October 31, 2013 Assuming an equal chance of landing face up and landing face down... P (face down >= 51) = Sum from i = 51 to 100 of (100 C i) * 2^100 Works out to what superprismatic came up with: 0.4602... Quote Link to comment Share on other sites More sharing options...
0 bonanova Posted November 1, 2013 Report Share Posted November 1, 2013 it's 0.5 - 1/2 p(50). Exercise left to the reader. Quote Link to comment Share on other sites More sharing options...
0 Dariusray Posted November 1, 2013 Report Share Posted November 1, 2013 ...the side with more ink by weight would be more likely to land downward? Quote Link to comment Share on other sites More sharing options...
0 dgreening Posted November 1, 2013 Report Share Posted November 1, 2013 ...the side with more ink by weight would be more likely to land downward? I like that! Any idea which side that is? Quote Link to comment Share on other sites More sharing options...
0 dgreening Posted November 4, 2013 Report Share Posted November 4, 2013 Another real world question ... When I read the question, I think of a tall building IN A CITY! If this is the case [or even if it is a single tall building surrounded by country side - where there might be trees]. it is very likely that some portion of the bills will not land "on the ground" [in trees, window sills, fire escapes, tops of cars or trash cans, ...]. If we are simply looking at the pure probability of 100 coin tosses [or bill flutters], then i think the answer above is probably right, if we add a real world setting, the answer may be much lower. It is probably just the lingering effects of too much sugar from Halloween. Quote Link to comment Share on other sites More sharing options...
0 Prime Posted November 7, 2013 Report Share Posted November 7, 2013 Chances are, most of the $100 bills would end up in the hands of very excited people below and not on the ground. By the way, have you chosen a specific building for that important experiment in probability? When? Quote Link to comment Share on other sites More sharing options...
0 DeGe Posted November 8, 2013 Report Share Posted November 8, 2013 There are 101 different possibilities from 0 to 100 up sides. Of these, 50 are cases where there are more up sides (from 51 to100). The probability then is 50/101 = 0.495 Quote Link to comment Share on other sites More sharing options...
0 TimeSpaceLightForce Posted November 16, 2013 Author Report Share Posted November 16, 2013 yes,correct.. like 100 time toss of a coin (though it may stand on its side when curved) for 2 times toss of a coin the chance is 25% same: combin(2,1)/2^2= 0.50000 more : (1-.5)/2= 0.25000 for 4 times toss of a coin the chance is 31.25% same: combin(4,2)/2^4= 0.37500 more: (1-.375)/2= 0.31250 for 100 times toss of a coin the chance is 46% same: combin(100,50)/2^100= 0.07959 more: (1-.07959)/2= 0.46021 Quote Link to comment Share on other sites More sharing options...
Question
TimeSpaceLightForce
If i toss 100 dollar bills from the top of a building ,what is the chance that more of them landing up side down on the ground?
Link to comment
Share on other sites
9 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.