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# Averages Part II

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Posted 29 July 2013 - 04:23 PM

This one may be too easy for brainden but why not, sometimes it is the obvious that proves most challenging.

Find an average height of the bars (you cannot throw out any elements of the data).  Use a strategy that best calculates the average which is most representative of the population. Show that your solution is the best.

The numbers underneath the bars represent the heights of each bar.

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### #2 Pickett

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Posted 29 July 2013 - 04:44 PM

Spoiler for don't suppose

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### #3 gavinksong

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Posted 29 July 2013 - 05:03 PM

Isn't the strategy for calculate the average always the same (add up all the values and then divide)?

Spoiler for

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Posted 29 July 2013 - 06:50 PM

There are many types of strategies for determining 'average'. Which is the best with this dataset?
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### #5 Pickett

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Posted 29 July 2013 - 07:42 PM

Spoiler for Well in my experience

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Posted 29 July 2013 - 08:11 PM

Is there no more precise calculation?

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### #7 DeGe

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Posted 30 July 2013 - 11:53 PM

Is there no more precise calculation?

Do you mean something like... Avg X with a standard deviation of y?

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### #8 vinay.singh84

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Posted 31 July 2013 - 06:10 PM

Spoiler for An average-finding method I learned when I was young

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### #9 bonanova

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Posted 31 July 2013 - 06:27 PM

Spoiler for An average-finding method I learned when I was young

Is this easier than just computing the average directly?

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Vidi vici veni.

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Posted 31 July 2013 - 07:21 PM

Spoiler for An average-finding method I learned when I was young

Is this easier than just computing the average directly?

this method is very easy with small data sets or data sets with a significant mode subset

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